Solution: Find the values of x, where 0 ≤ x ≤ 360, such that 2sin^2 x + 5cosx + 1 = 0 engr 3 years ago Facebook Prev Article Next Article (Last Updated On: December 8, 2017) Problem Statement: Find the values of x, where 0 ≤ x ≤ 360, such that 2sin2x + 5cosx + 1 = 0. Problem Answer: x = 120° or 240° Solution: 0.0 00 If you liked this, then please subscribe to our YouTube Channel for engineering video tutorials. You can also find us on Twitter and Facebook. Facebook Prev Article Next Article Add Comment Cancel reply Notify me of follow-up comments by email. Notify me of new posts by email.