This is the Multiples Choice Questions Part 10 of the Series in Power Generators, Sources, Principles and Applications as one of the Electronics Engineering topic. In Preparation for the ECE Board Exam make sure to expose yourself and familiarize in each and every questions compiled here taken from various sources including but not limited to past Board Exam Questions in Electronics Engineering field, Electronics Books, Journals and other Electronics References.
MCQ Topic Outline included in ECE Board Exam Syllabi
- MCQ in Cells and Batteries
- MCQ in Electric Generator
- MCQ in Electronic Power Supply
- MCQ in Voltage Regulation
- MCQ in Photovoltaic/Thermoelectric Generator
- MCQ in Distribution Transformer
- MCQ in Uninterrupted Power Supply (UPS)
- MCQ in Float-Battery System
- MCQ in Converters
- MCQ in Inverters
Continue Practice Exam Test Questions Part 10 of the Series
Choose the letter of the best answer in each questions.
451. ECE Board Exam April 1998
What is the other term of the secondary cells considering its capability to accept recharging?
A. Reaction cell
B. Primary cell
C. Storage cell
D. Dry cell
Answer: Option C
Solution:
452. ECE Board Exam November 1996
Find the required battery capacity needed to operate an equipment of 30 amperes at 5 hours.
A. 6
B. 30
C. 3
D. 150
Answer: Option D
Solution:
453. ECE Board Exam March 1996
When batteries have cells connected in series the effect is
A. Reduced output voltage
B. Increased current supply
C. Increased voltage supply
D. Reduced internal resistance
Answer: Option C
Solution:
454. ECE Board Exam November 2000
Find the required battery capacity needed to operate on electronic equipment with power rating of 200 watts and 10 volts at 6 hours.
A. 60
B. 1200
C. 20
D. 120
Answer: Option D
Solution:
455. ECE Board Exam November 2000
A cell(s) that can be operated or used in a horizontal, vertical or any position where its electrolyte cannot be spilled in any position
A. Primary cells
B. Secondary cells
C. Dry cells
D. Battery
Answer: Option A
Solution:
456. ECE Board Exam April 1999
It is an indication of the current supplying capability of the battery for a specific period of time, e.g. 400 ampere-hour.
A. Rating
B. Capacity
C. Capability
D. Current load
Answer: Option B
Solution:
457. ECE Board Exam March 1996
Which of the following is not a secondary type cell?
A. Lithium
B. Lead-acid
C. Silver cadmium
D. Silver-zinc
Answer: Option A
Solution:
458. ECE Board Exam March 1996
How many lithium cells in series are needed for a 12 V battery?
A. 12 cells
B. 4 cells
C. 8 cells
D. 10 cells
Answer: Option B
Solution:
459. ECE Board Exam November 1996
Component of solar battery which uses light energy to produce electromagnetic force
A. Alkaline cell
B. Polymer cell
C. Lithium cell
D. Selenium cell
Answer: Option D
Solution:
460. ECE Board Exam March 1996
If a dry cell has an internal resistance of 0.50 ohm and emf of 2 volts, find power delivered in a one ohm resistor.
A. 1.33 watts
B. 1.66 watts
C. 3.66 watts
D. 1.77 watts
Answer: Option A
Solution:
461. ECE Board Exam March 1996
Parallel cells have the same voltage as one cell but have ___________.
A. Unstable resistance
B. Less current capability
C. Fluctuating power output
D. More current capacity
Answer: Option D
Solution:
462. ECE Board Exam April 1999
A battery with capacity of 100 Ah and 12 volts rating will run an electronic equipment at exactly 20 hours, how much power is needed?
A. 60 watts
B. 20 watts
C. 10 watts
D. 30 watts
Answer: Option A
Solution:
463. ECE Board Exam March 1996
It is the output voltage of a carbon-zinc cell.
A. 3.5 V
B. 2.5 V
C. 1.5 V
D. 0.5 V
Answer: Option C
Solution:
464. ECE Board Exam March 1996
What is the reason why more cells can be stored in a given area with dynamic cells?
A. They consume less power
B. They are smaller
C. They are larger
D. They travel faster
Answer: Option B
Solution:
465. ECE Board Exam November 1997
A radio equipment will be used at 70% at 50 amperes rating for 5 hours. How much capacity of dry battery is needed?
A. 35
B. 17.5
C. 250
D. 175
Answer: Option D
Solution:
466. The potential at the terminals of the battery falls from 9 V on open circuit to 6 volts when a resistor of 10 ohms is connected across its terminals. What is the internal resistance of the battery?
A. 5 ฮฉ
B. 4 ฮฉ
C. 3 ฮฉ
D. 2 ฮฉ
Answer: Option A
Solution:
467. A battery is formed of five cells joined in series. When the external resistance is 4 ohms, the current is 1.5 A and when the external resistance is 9 ohms, the current falls to 0.75 A. Find the internal resistance of each cell.
A. 0.5 ohm
B. 1.0 ohm
C. 0.2 ohm
D. 0.3 ohm
Answer: Option C
Solution:
468. A 12 V source with 0.05 ฮฉ resistance is connected in series with another 12 volt with 0.075 ฮฉ resistance with a load of 2 ฮฉ. Calculate the power dissipated in the load.
A. 365 watts
B. 127 watts
C. 105 watts
D. 255 watts
Answer: Option D
Solution:
469. A 24 V source with 0.05 ฮฉ resistance is connected in parallel with another 24 V with 0.075 ฮฉ resistance to a load of 2 ฮฉ. Calculate the current delivered by the source with a 0.05 ฮฉ resistor.
A. 7 amperes
B. 10 amperes
C. 5 amperes
D. 12 amperes
Answer: Option A
Solution:
470. A battery can deliver 10 joules of energy to move 5 coulombs of charge. What is the potential difference between the terminals of the battery?
A. 2 V
B. 50 V
C. 0.5 V
D. 5 V
Answer: Option A
Solution:
471. An ordinary dry cell can deliver about ________ continuously.
A. 3 A
B. 2 A
C. 1/8 A
D. none of the above
Answer: Option C
Solution:
472. Cells are connected in series when _________ is required.
A. high voltage
B. high current
C. high voltage as well as high current
D. none of the above
Answer: Option A
Solution:
473. Cells are connected in seriesโparallel when _________ is required.
A. high current
B. high voltage
C. high current as well a high voltage
D. none of the above
Answer: Option C
Solution:
474. Four cells, each of internal resistance 1 ohm, are connected in parallel. The battery resistance will be _________
A. 4 ohms
B. 0.25 ohm
C. 2 ohms
D. 1 ohm
Answer: Option B
Solution:
475. The e.m.f. of a cell depends upon _________
A. nature of electrodes and electrolyte
B. size of electrodes
C. spacing between electrodes
D. none of the above
Answer: Option A
Solution:
476. In order to get maximum current in series โ parallel grouping, the external resistance should be ________ the total internal resistance of the battery.
A. less than
B. more than
C. equal to
D. none of the above
Answer: Option C
Solution:
477. The positive terminal of a 6-V battery is connected to the negative terminal of a 12-V battery whose positive terminal is grounded. The potential at the negative terminal of the 6-V battery is ________ volt.
A. +18
B. โ12
C. โ6
D. -18
Answer: Option D
Solution:
478. The positive terminal of a 6-V battery is connected to the negative terminal of a 12-V battery whose positive terminal is grounded. The potential at the positive terminal of the 6-V battery is ______ volt.
A. +6
B. โ6
C. โ12
D. +12
Answer: Option C
Solution:
479. Active materials of a lead-acid cell are
A. lead peroxide
B. sponge lead
C. dilute sulfuric acid
D. all of these
Answer: Option D
Solution:
480. During the charging of lead-acid cell
A. its cathode becomes dark chocolate brown in colour
B. its voltage increases
C. it gives out energy
D. specific gravity of H2SO4 is decreased
Answer: Option B
Solution:
481. The ratio of Ah efficiency to Wh efficiency of a lead-acid cell is
A. always less than one
B. just one
C. always greater than one
D. either A or B
Answer: Option C
Solution:
482. The capacity of a cell is measured in
A. watt-hours
B. watts
C. amperes
D. ampere-hours
Answer: Option D
Solution:
483. The capacity of a lead-acid cell does NOT depend on its
A. rate of charge
B. rate of discharge
C. temperature
D. quantity of active materials
Answer: Option A
Solution:
484. As compared to constant-current system, the constant-voltage system of charging a lead-acid cell has the advantage of
A. avoiding excessive gassing
B. reducing time of charging
C. increasing cell capacity
D. both B and C
Answer: Option D
Solution:
485. Sulphation in a lead-acid battery occurs due to
A. trickle charging
B. incomplete charging
C. heavy discharging
D. fast charging
Answer: Option B
Solution:
486. The active materials of a nickel-iron battery are
A. nickel hydroxide
B. powdered iron and its oxides
C. 21% solution of caustic potash
D. all of these
Answer: Option D
Solution:
487. During charging and discharging of a nickel-iron cell
A. its e.m.f. remains constant
B. water is neither formed nor absorbed
C. corrosive fumes are produced
D. nickel hydroxide remains unsplit
Answer: Option B
Solution:
488. As compared to a lead-acid cell, the efficiency of a nickel-iron cell is less due to its
A. lower e.m.f.
B. smaller quantity of electrolyte used
C. higher internal resistance
D. compactness
Answer: Option C
Solution:
489. Trickle charging of a storage battery helps to
A. prevent sulphation
B. keep it fresh and fully charged
C. maintain proper electrolyte level
D. increase its reserve capacity
Answer: Option B
Solution:
490. A dead storage battery can be revived by
A. a dose of H2SO4
B. adding so-called battery restorer
C. adding distilled water
D. none of these
Answer: Option D
Solution:
491. The sediment which accumulates at the bottom of a lead-acid battery consist largely of
A. lead-peroxide
B. lead-sulphate
C. antimony-lead alloy
D. graphite
Answer: Option C
Solution:
492. The reduction of battery capacity at high rates of discharge is primarily due to
A. increase in its internal resistance
B. decrease in its terminal voltage
C. rapid formation of PbSO4 on the plates
D. non-diffusion of acid to the inside active materials
Answer: Option C
Solution:
493. Floating battery system are widely used for
A. power stations
B. emergency lighting
C. telephone exchange installation
D. all of these
Answer: Option D
Solution:
494. Any charge given to the battery when taken off the vehicle is called
A. bench charge
B. step charge
C. float charge
D. trickle charge
Answer: Option A
Solution:
495. Storage battery electrolyte is formed by the dissolving of ________ acid in water.
A. hydrochloric
B. sulfuric
C. acetic
D. atric
Answer: Option B
Solution:
496. The central terminal of a dry cell is said to be
A. positive
B. negative
C. neutral
D. charged
Answer: Option A
Solution:
497. A 24 V battery of internal resistance r = 4 โฆ is connected to a variable resistance R, the rate of heat dissipation in the resistor is maximum when the current drawn from the battery is I. Current drawn from the battery will be I/2 when R is equal to
A. 8 โฆ
B. 12 โฆ
C. 16 โฆ
D. 20 โฆ
Answer: Option B
Solution:
498. What is the other term used for rechargeable battery?
A. primary
B. lead-acid
C. storage
D. nickel-cadmium
Answer: Option C
Solution:
499. Technique(s) in using low-power, low-voltage transistors in high voltage regulators.
A. ground return regulation
B. by lifting the regulator above ground
C. connecting them in series
D. all of the above
Answer: Option D
Solution:
500. Which of the regulators dissipates less power and therefore generates less heat?
A. series
B. shunt
C. switching
D. UPS
Answer: Option C
Solution:
501. In switching regulators, what are the semiconductor devices that can be used as controllable power switches?
A. BJTs and MDs
B. MOSFETs and IGBT
C. GTOs and thyristors
D. all of the above
Answer: Option D
Solution:
502. In voltage regulators, the control element plays a major part in providing proper and efficient regulation. What are the desirable characteristics of the control element to be used if excellent regulator is desired?
A. very small off-state leakage current and high on-state current ratings
B. large forward and reverse blocking voltage and very small on-sate voltage
C. short turn-on and turn-off times so that it can be used in high-speed switching regulators
D. all of the above
Answer: Option D
Solution:
503. Active devices used in switching regulators may experience large over-currents during conduction (turn-on-state) and large over-voltages during turn-off. These excessive currents and voltages may cause distraction or damage of the active devices. How do we protect them?
A. by the use of a crowbar circuit
B. by providing a buck-boost circuit
C. by shunting a thyrector
D. by installing a snubber circuit
Answer: Option D
Solution:
504. One of the major concerns in power electronics is to clean-up or shape-up the utility-supply voltage (the wall-outlet 220 V/60 Hz) from disturbances such as, overvolt, undervolt, voltage spikes, and harmonic distortions. What circuit is used for this?
A. power conditioners
B. UPS
C. power inverters
D. line scanning
Answer: Option A
Solution:
505. A power supply that continuously provides protection against under-voltage, overvoltage and even power outages.
A. standby power supply
B. uninterruptible power supply
C. power conditioners
D. regulated power supply
Answer: Option B
Solution:
Questions and Answers in Power Generators, Sources, Principles, Applications
Following is the list of practice exam test questions in this brand new series:
Complete List of MCQs in Electronics Engineering per topic
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