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(Last Updated On: December 4, 2018)

Solve xy’ (2y – 1) = y (1 – x)

A. ln (xy) = 2 (x – y) + C

B. ln (xy) = x – 2y + C

C. ln (xy) = 2y – x + C

D. ln (xy) = x + 2y + C

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