MCQ in Quadratic Equation, Binomial Theorem and Logarithms Part 1 | Math Board Exam

MCQ in Quadratic Equation, Binomial Theorem and Logarithms Part 1 | ECE Board Exam

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MASTER YOUR MATH BOARD EXAM: Power Through Quadratic Equations, Binomial Theorem & Logarithms

DOMINATE these critical Engineering Mathematics topics with our comprehensive MCQ collection!

Engineers, this is your gateway to conquering one of the most challenging sections on your board exam. Our expertly curated Multiple Choice Questions (Part 1) on Quadratic Equations, Binomial Theorem, and Logarithms will transform your preparation from ordinary to EXTRAORDINARY.

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Multiple Choice Questions Topic Outline

MCQ in Basic Rules in Quadratic Formula | MCQ in Nature of Roots | MCQ in Properties of Roots | MCQ in Binomial Theorem | MCQ in Properties of Expansion | MCQ in Pascal’s Triangle | MCQ in Coefficient of any term | MCQ in Formula for rth term | MCQ in Sum of Coefficients | MCQ in Sum of Exponents | MCQ in Common and Natural Logarithms | MCQ in Euler’s Number | MCQ in Binary Logarithms | MCQ in Properties of Logarithms

Start Practice Exam Test Questions Part 1 of the Series

Choose the letter of the best answer in each question.

Problem 1: ECE Board March 1996

The equation whose roots are the reciprocals of the roots of 2x2 – 3x – 5 = 0 is,

A. 5x2 + 3x – 2 = 0

B. 2x2 + 3x – 5 = 0

C. 3x2 – 3x +2 = 0

D. 2x2 + 5x – 3 = 0

Problem 2: EE Board October 1993

In the equation x2 + x = 0, one root is x equal to

A. 1

B. 5

C. ¼

D. None of these

View Answer:

Problem 3: ECE Board April 1990

Solve for the value of “a” in the equation a8 – 17a4 + 16 = 0

A. ± 2

B. ± 3

C. ± 4

D. ± 5

Problem 4: ME Board October 1996

Solve for x that satisfies the equation 6x2 – 7x – 5 = 0

A. 5/3 or -1/2

B. 3/2 or 3/8

C. 7/5 or -7/15

D. 3/5 or 3/4

Problem 5: EE Board October 1997

Find the values of x in the equation 24x2 + 5x – 1 = 0

A. (1/6, 1)

B. (1/6, 1/5)

C. (1/2, 1/5)

D. (1/8, -1/3)

View Answer:

Problem 6: EE Board October 1990

Determine k so that the equation 4x2 + kx + 1 = 0 will have just one real solution.

A. 3

B. 4

C. 5

D. 6

Problem 7: ME Board April 1996

Solve for x: 10x2 + 10x + 1 = 0

A. -0.113, -0.887

B. -0.331, -0.788

C. -0.113, -0.788

D. -0.311, -0.887

View Answer:

Problem 8:

If 1/3 and -3/2 are roots of a quadratic equation, then the equation is

A. 6x2 + 7x – 3 = 0

B. 6x2 – 7x + 3 = 0

C. 6x2 – 7x – 3 = 0

D. 6x2 – 7x + 1 = 0

Problem 9:

Which of the following is a root of this quadratic equation 30x2 + 49x + 20 = 0

A. 0.6

B. -0.6

C. -0.8

D. 0.75

View Answer:

Problem 10:

What is the discriminant of the equation 4x2 = 8x – 5?

A. 8

B. -16

C. 16

D. -8

View Answer:

Problem 11:

Given the equation 3x2 + Bx + 12 = 0. What is the value of B so that the roots of the equation are equal?

A. 4

B. 8

C. 10

D. -12

Problem 12:

Find the term involving y5 in the expansion of (2x2 + y)10.

A. 8064x10y5

B. 8046x5y5

C. 8046x10y5

D. 4680x5y5

View Answer:

Problem 13:

Find the 5th term of the expansion of (x2 +1/x)10

A. 260x8

B. 5040x8

C. 210x8

D. 420x8

View Answer:

Problem 14: ECE Board April 1998

In the expression of (x + 4y)12, the numerical coefficient of the 5th term is,

A. 63,360

B. 126,720

C. 506,880

D. 253,440

Problem 15:

What is the fourth term of the expansion of (x + x2)100?

A. 1650x103

B. 161700x103

C. 167100x103

D. 167100x100

View Answer:

Problem 16:

What is the numerical coefficient of the term next to 495x8y4?

A. 660

B. 792

C. 990

D. 1100

Problem 17: CE Board November 1996

Find the 6th term of the expansion of (1/2a – 3)16.

A. – 66939/256a11

B. – 66339/128a11

C. – 33669/256a11

D. – 39396/128a11

View Answer:

Problem 18:

What is the coefficient of the term free of x of the expansion of (2x – 5y)4?

A. 256

B. 526

C. 265

D. 625

Problem 19:

Find the 6th term of (3x – 4y)8?

A. -148,288 x3y5

B. -548 x2y5

C. -154,288 x3y5

D. -1,548,288 x3y5

View Answer:

Problem 20: ECE Board November 1995

What is the sum of the coefficients of the expansion (2x – 1)20?

A. 0

B. 1

C. 2

D. 3

Problem 21: ECE Board April 1995

What is the sum of the coefficients in the expansion (x + y – z)8?

A. 0

B. 1

C. 2

D. 3

Problem 22: CE Board November 1993, ECE Board November 1993

Find the value of log8 48.

A. 1.86

B. 1.68

C. 1.78

D. 1.98

View Answer:

Answer: Option A

Solution:Find the value of log 48 to the base 8

Problem 23: CE Board November 1997

Evaluate the log6 845 = x

A. 3.76

B. 5.84

C. 4.48

D. 2.98

View Answer:

Answer: Option A

Solution:Evaluate the log 845 to the base 6=x

Problem 24: ME Board April 1997

What is the value of log to base 10 of 10003.3?

A.10.9

B. 99.9

C. 9.9

D. 9.5

View Answer:

Problem 25: ECE Board April 1998

What is the value of (log 5 to the base 2) + (log 5 to the base 3)?

A.7.39

B. 3.79

C. 3.97

D. 9.37

Problem 26:

Find the value of log4 (log3 5).

A.1.460

B. 0.275

C. 1.273

D. 0.165

View Answer:

Problem 27:

Given: log4 7 = n. Find log4 1/7.

A. 1/n

B. n

C. -1/n

D. –n

View Answer:

Problem 28: CE Board November 1992, CE Board May 1994

If loga 10 = 0.25, what is the value of log10 a?

A. 2

B. 4

C. 6

D. 8

Problem 29: ECE Board November 1995

Given logb y = 2x + logb x. Which of the following is true?

A. y = b2x

B. y = 2xb

C. y = 2x/b

D. y = xb2x

Problem 30: ME Board October 1996

Which value is equal to log to the base e of e to the -7x power?

A. -7x

B. 10 to the -7x power

C. 7

D. -7 log to the base 10

Problem 31: ME Board April 1996

Log of the nth root of x equals log of x to 1/n power and also equal to

A. (log x)/n

B. nlog x

C. {log (x to the 1/n power)}/n

D. (n -1) log x

Problem 32: ECE Board November 1990

Log (MN) is equal to:

a. Log M – N

B. Log M + N

C. N log M

D. Log M + Log N

View Answer:

Answer: Option D

Solution:What is the equivalent of Log (MN)?

Problem 33: ME Board April 1997

What expression is equivalent to log (x) – log (y + z)?

A. log x + log y + log z

B. log [x/(y + z)]

C. log x – log y – log z

D. log y + log (x +z)

View Answer:

Problem 34: ECE Board November 1991

Given: logb 1024 = 5/2. Find b.

A. 2560

B. 16

C. 4

D. 2

View Answer:

Answer: Option B

Solution:Given log 1024 to the base b=5/2. Find b

Problem 35:

Given: log3 (x2 – 8x) = 2. Find x.

A. -1

B. 9

C. -1 and 9

D. 1 and -9

View Answer:

Problem 36: ECE Board November 1991

Solve for the value of x in the following equation: x3logx = 100x

A. 12

b. 8

C. 30

D. 10

Problem 37: EE Board October 1992

Given: log 6 + x log 4 = log 4 + log (32 + 4x). Find x.

A. 2

B. 3

C. 4

D. 6

View Answer:

Problem 38: ECE Board November 1998

If log of 2 to the base 2 plus log of x to the base 2 is equal to 2, then the value of x is

A. 4

B. -2

C. 2

D. -1

Problem 39: ME Board October 1997

Find the value of x if log12 x = 2

A. 144

B. 414

C. 524

D. 425

View Answer:

Problem 40:

Solve for the value of x:

log 2x3 + log 6/x = 6.278

A. 379.65

B. 365.97

C. 397.56

D. 356.79

View Answer:

Online Questions and Answers in Quadratic Equation, Binomial Theorem and Logarithms Series

Quadratic Equation, Binomial Theorem and Logarithms MCQs
PART 1: MCQs from Number 1 – 50                        Answer key: PART 1
PART 2: MCQs from Number 51 – 100                   Answer key: PART 2

Mathematics Board Examination Mastery | Math Engineering Pre-Board

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