
MASTER YOUR MATH BOARD EXAM: Power Through Quadratic Equations, Binomial Theorem & Logarithms
DOMINATE these critical Engineering Mathematics topics with our comprehensive MCQ collection!
Engineers, this is your gateway to conquering one of the most challenging sections on your board exam. Our expertly curated Multiple Choice Questions (Part 1) on Quadratic Equations, Binomial Theorem, and Logarithms will transform your preparation from ordinary to EXTRAORDINARY.
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Multiple Choice Questions Topic Outline
MCQ in Basic Rules in Quadratic Formula | MCQ in Nature of Roots | MCQ in Properties of Roots | MCQ in Binomial Theorem | MCQ in Properties of Expansion | MCQ in Pascal’s Triangle | MCQ in Coefficient of any term | MCQ in Formula for rth term | MCQ in Sum of Coefficients | MCQ in Sum of Exponents | MCQ in Common and Natural Logarithms | MCQ in Euler’s Number | MCQ in Binary Logarithms | MCQ in Properties of Logarithms
Start Practice Exam Test Questions Part 1 of the Series
Choose the letter of the best answer in each question.
Problem 1: ECE Board March 1996
The equation whose roots are the reciprocals of the roots of 2x2 – 3x – 5 = 0 is,
A. 5x2 + 3x – 2 = 0
B. 2x2 + 3x – 5 = 0
C. 3x2 – 3x +2 = 0
D. 2x2 + 5x – 3 = 0
Answer: Option A
Solution:Find the equation whose roots are the reciprocals of the roots of the given equation
Problem 2: EE Board October 1993
In the equation x2 + x = 0, one root is x equal to
A. 1
B. 5
C. ¼
D. None of these
Answer: Option D
Solution:In the equation x^2+x=0, what are the roots equal to?
Problem 3: ECE Board April 1990
Solve for the value of “a” in the equation a8 – 17a4 + 16 = 0
A. ± 2
B. ± 3
C. ± 4
D. ± 5
Answer: Option A
Solution:Solve for the value of “a” in the equation a^8–17a^4+16=0
Problem 4: ME Board October 1996
Solve for x that satisfies the equation 6x2 – 7x – 5 = 0
A. 5/3 or -1/2
B. 3/2 or 3/8
C. 7/5 or -7/15
D. 3/5 or 3/4
Answer: Option A
Solution:Solve for x that satisfies the equation 6x^2 – 7x – 5 = 0
Problem 5: EE Board October 1997
Find the values of x in the equation 24x2 + 5x – 1 = 0
A. (1/6, 1)
B. (1/6, 1/5)
C. (1/2, 1/5)
D. (1/8, -1/3)
Answer: Option D
Solution:Find the values of x in the equation 24x^2 + 5x – 1 = 0
Problem 6: EE Board October 1990
Determine k so that the equation 4x2 + kx + 1 = 0 will have just one real solution.
A. 3
B. 4
C. 5
D. 6
Answer: Option B
Solution:Determine k so that the equation 4x^2 + kx + 1 = 0 will have just one real solution
Problem 7: ME Board April 1996
Solve for x: 10x2 + 10x + 1 = 0
A. -0.113, -0.887
B. -0.331, -0.788
C. -0.113, -0.788
D. -0.311, -0.887
Answer: Option A
Solution: Solve for the value of x in the equation 10x^2+10x+1=0
Problem 8:
If 1/3 and -3/2 are roots of a quadratic equation, then the equation is
A. 6x2 + 7x – 3 = 0
B. 6x2 – 7x + 3 = 0
C. 6x2 – 7x – 3 = 0
D. 6x2 – 7x + 1 = 0
Answer: Option A
Solution:If 1/3 and -3/2 are roots of a quadratic equation, then what is the equation?
Problem 9:
Which of the following is a root of this quadratic equation 30x2 + 49x + 20 = 0
A. 0.6
B. -0.6
C. -0.8
D. 0.75
Answer: Option C
Problem 10:
What is the discriminant of the equation 4x2 = 8x – 5?
A. 8
B. -16
C. 16
D. -8
Answer: Option B
Solution:What is the discriminant of the equation 4x^2=8x–5?
Problem 11:
Given the equation 3x2 + Bx + 12 = 0. What is the value of B so that the roots of the equation are equal?
A. 4
B. 8
C. 10
D. -12
Answer: Option D
Solution:What is the value of B so that the roots of the equation are equal?
Problem 12:
Find the term involving y5 in the expansion of (2x2 + y)10.
A. 8064x10y5
B. 8046x5y5
C. 8046x10y5
D. 4680x5y5
Answer: Option A
Solution:Find the term involving y^5 in the expansion of (2x^2+y)^10
Problem 13:
Find the 5th term of the expansion of (x2 +1/x)10
A. 260x8
B. 5040x8
C. 210x8
D. 420x8
Answer: Option C
Problem 14: ECE Board April 1998
In the expression of (x + 4y)12, the numerical coefficient of the 5th term is,
A. 63,360
B. 126,720
C. 506,880
D. 253,440
Answer: Option B
Solution:In the expression of (x+4y)^12, What is the numerical coefficient of the 5th term?
Problem 15:
What is the fourth term of the expansion of (x + x2)100?
A. 1650x103
B. 161700x103
C. 167100x103
D. 167100x100
Answer: Option B
Solution:What is the fourth term of the expansion of (x+x^2)^100?
Problem 16:
What is the numerical coefficient of the term next to 495x8y4?
A. 660
B. 792
C. 990
D. 1100
Answer: Option B
Solution:What is the numerical coefficient of the term next to 495x^8y^4?
Problem 17: CE Board November 1996
Find the 6th term of the expansion of (1/2a – 3)16.
A. – 66939/256a11
B. – 66339/128a11
C. – 33669/256a11
D. – 39396/128a11
Answer: Option B
Problem 18:
What is the coefficient of the term free of x of the expansion of (2x – 5y)4?
A. 256
B. 526
C. 265
D. 625
Answer: Option D
Solution:What is the coefficient of the term free of x of the expansion of (2x–5y)^4?
Problem 19:
Find the 6th term of (3x – 4y)8?
A. -148,288 x3y5
B. -548 x2y5
C. -154,288 x3y5
D. -1,548,288 x3y5
Answer: Option D
Problem 20: ECE Board November 1995
What is the sum of the coefficients of the expansion (2x – 1)20?
A. 0
B. 1
C. 2
D. 3
Answer: Option A
Solution:What is the sum of the coefficients of the expansion (2x–1)^20?
Problem 21: ECE Board April 1995
What is the sum of the coefficients in the expansion (x + y – z)8?
A. 0
B. 1
C. 2
D. 3
Answer: Option B
Solution:What is the sum of the coefficients in the expansion (x+ y–z)^8?
Problem 22: CE Board November 1993, ECE Board November 1993
Find the value of log8 48.
A. 1.86
B. 1.68
C. 1.78
D. 1.98
Answer: Option A
Problem 23: CE Board November 1997
Evaluate the log6 845 = x
A. 3.76
B. 5.84
C. 4.48
D. 2.98
Answer: Option A
Solution:Evaluate the log 845 to the base 6=x
Problem 24: ME Board April 1997
What is the value of log to base 10 of 10003.3?
A.10.9
B. 99.9
C. 9.9
D. 9.5
Answer: Option C
Problem 25: ECE Board April 1998
What is the value of (log 5 to the base 2) + (log 5 to the base 3)?
A.7.39
B. 3.79
C. 3.97
D. 9.37
Answer: Option B
Solution:What is the value of (log 5 to the base 2)+(log 5 to the base 3)?
Problem 26:
Find the value of log4 (log3 5).
A.1.460
B. 0.275
C. 1.273
D. 0.165
Answer: Option B
Solution:Find the value of log to the base 4 of log 5 to the base 3
Problem 27:
Given: log4 7 = n. Find log4 1/7.
A. 1/n
B. n
C. -1/n
D. –n
Answer: Option D
Problem 28: CE Board November 1992, CE Board May 1994
If loga 10 = 0.25, what is the value of log10 a?
A. 2
B. 4
C. 6
D. 8
Answer: Option B
Solution:If log 10 to the base a=0.25, what is the value of log a to the base 10?
Problem 29: ECE Board November 1995
Given logb y = 2x + logb x. Which of the following is true?
A. y = b2x
B. y = 2xb
C. y = 2x/b
D. y = xb2x
Answer: Option D
Solution:Given log y to the base b=2x+log x to the base b. What is the value of y?
Problem 30: ME Board October 1996
Which value is equal to log to the base e of e to the -7x power?
A. -7x
B. 10 to the -7x power
C. 7
D. -7 log to the base 10
Answer: Option A
Solution:What value is equal to log to the base e of e to the -7x power?
Problem 31: ME Board April 1996
Log of the nth root of x equals log of x to 1/n power and also equal to
A. (log x)/n
B. nlog x
C. {log (x to the 1/n power)}/n
D. (n -1) log x
Answer: Option A
Solution:Log of the nth root of x equals log of x to 1/n power and also equal to
Problem 32: ECE Board November 1990
Log (MN) is equal to:
a. Log M – N
B. Log M + N
C. N log M
D. Log M + Log N
Answer: Option D
Solution:What is the equivalent of Log (MN)?
Problem 33: ME Board April 1997
What expression is equivalent to log (x) – log (y + z)?
A. log x + log y + log z
B. log [x/(y + z)]
C. log x – log y – log z
D. log y + log (x +z)
Answer: Option B
Solution:What expression is equivalent to log (x)-log (y+z)?
Problem 34: ECE Board November 1991
Given: logb 1024 = 5/2. Find b.
A. 2560
B. 16
C. 4
D. 2
Answer: Option B
Problem 35:
Given: log3 (x2 – 8x) = 2. Find x.
A. -1
B. 9
C. -1 and 9
D. 1 and -9
Answer: Option C
Problem 36: ECE Board November 1991
Solve for the value of x in the following equation: x3logx = 100x
A. 12
b. 8
C. 30
D. 10
Answer: Option D
Solution:Solve for the value of x in the following equation: x^(3log x)=100x
Problem 37: EE Board October 1992
Given: log 6 + x log 4 = log 4 + log (32 + 4x). Find x.
A. 2
B. 3
C. 4
D. 6
Answer: Option B
Problem 38: ECE Board November 1998
If log of 2 to the base 2 plus log of x to the base 2 is equal to 2, then the value of x is
A. 4
B. -2
C. 2
D. -1
Answer: Option C
Solution:If log of 2 to the base 2 + log of x to the base 2 = 2. Find x
Problem 39: ME Board October 1997
Find the value of x if log12 x = 2
A. 144
B. 414
C. 524
D. 425
Answer: Option A
Problem 40:
Solve for the value of x:
log 2x3 + log 6/x = 6.278
A. 379.65
B. 365.97
C. 397.56
D. 356.79
Answer: Option C
Online Questions and Answers in Quadratic Equation, Binomial Theorem and Logarithms Series
Mathematics Board Examination Mastery | Math Engineering Pre-Board
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