#### Problem Statement: ME Board April 1996

Log of the nth root of x equals log of x to 1/n power and also equal to

- A. (logx)/n
- B. nlogx
- C. [(log(x to the 1/n power)]/n
- D. (n-1)logx

#### Problem Answer:

The expression is also equal to **(log x)/n**.

Solution:

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