#### Problem Statement: EE Board October 1991

A simply supported beam is 5 meters in length. It carries a uniformly distributed load including its own weight of 300 N/m and a concentrated load of 100 N, 2 meters from the left end. Find the reactions if reaction A is at the left end and reaction B at the right end.

- A. Ra = 810 N & Rb = 700 N
- B. Ra = 700 N & Rb = 800 N
- C. Ra = 810 N & Rb = 780 N
- D. Ra = 700 N & Rb = 810 N

#### Problem Answer:

The reactions of the beam is **Ra = 810 N & Rb = 700 N**.

### Latest Problem Solving in Statics

More Questions in: Engineering Mechanics Statics

Rb should be 790

Take summation of moments in Ra be Zero

100(2)+1500(2.5)=5Rb

Rb= 790

Rb should be 790.