#### Problem Statement: EE Board October 1991

A simply supported beam is 5 meters in length. It carries a uniformly distributed load including its own weight of 300 N/m and a concentrated load of 100 N, 2 meters from the left end. Find the reactions if reaction A is at the left end and reaction B at the right end.

- A. Ra = 810 N & Rb = 700 N
- B. Ra = 700 N & Rb = 800 N
- C. Ra = 810 N & Rb = 780 N
- D. Ra = 700 N & Rb = 810 N

#### Problem Answer:

The reactions of the beam is **Ra = 810 N & Rb = 700 N**.

### Latest Problem Solving in Statics

More Questions in: Engineering Mechanics Statics

#### Online Questions and Answers in Engineering Mechanics Statics

If you liked this, then please subscribe to our YouTube Channel for engineering video tutorials. You can also find us on Twitter and Facebook.

Rb should be 790

Take summation of moments in Ra be Zero

100(2)+1500(2.5)=5Rb

Rb= 790

Rb should be 790.