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# Solution: Find E at P(15, 20, 50) cm

#### Problem Statement: Electromagnetics

Electric Field Intensity Problem Solving

A charge of -0.3 ฮผC is located at A(25, -30, 15) (in cm), and a second charge of 0.5 ฮผC is at B(-10, 8, 12) cm. Find E at P(15, 20, 50) cm.

A. 0.52ax – 12.4ay + 11.9az kV/m

B. 11.9ax – 0.52ay + 12.4az kV/m

C. -11.9ax – 0.52ay โ 12.4az kV/m

D. -0.52ax – 12.4ay โ 11.9az kV/m

The E at P(15, 20, 50) cm is equal to 11.93ax – 0.52ay + 12.41az kV/m.

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