Problem Statement: Electromagnetics
Electric Field Intensity Problem SolvingA small object of mass 3.80 g and charge -18 ฮผC is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. What are the magnitude and direction of the electric field?
A. -4.89 ร 10^3 N/C
B. -3.15 x 10^3 N/C
C. -1.63 ร 10^3 N/C
D. -2.07 ร 10^3 N/C
Problem Answer:
The magnitude and direction of the electric field is equal to -2.071 ร 10^3 N/C (downwards).
View Solution:
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