
Multiple Choice Questions in Plane Trigonometry – Part 1 | ECE Board Exam Practice
If you’re reviewing for the ECE Board Exam, plane trigonometry is one topic you simply can’t afford to skip. It shows up consistently in the Engineering Mathematics section, and getting it right can make a real difference in your overall score.
This is Part 1 of the MCQ Series in Plane Trigonometry, compiled to help electronics engineering students get enough practice before exam day. The questions are drawn from actual past ECE Board Exam problems, engineering mathematics textbooks, academic journals, and other trusted references, so you’re working with material that actually counts.
Go through each item carefully. Don’t just memorize the answers; you need to understand why each solution works. That habit alone separates the passers from the repeaters.
Whether you’re just starting your review or doing a final run-through, this is a good place to begin.
Multiple Choice Questions Topic Outline
MCQ in Trigonometry | MCQ in Solution to Right Triangles | MCQ in Pythagorean Theorem | MCQ in Solution to Oblique Triangles | MCQ in Law of Sines | MCQ in Law of Cosines | MCQ in Law of Tangents | MCQ in Trigonometric Identities | MCQ in Plane Areas (Triangles) | MCQ in Plane Areas (Quadrilaterals) | MCQ in Ptolemy’s Theorem
Start Practice Exam Test Questions Part 1 of the Series
Choose the letter of the best answer in each question.
Problem 1: ECE Board April 1999
Sin (B – A) is equal to _______, when B = 270 degrees and A is an acute angle.
A. – cos A
B. cos A
C. – sin A
D. sin A
Answer: Option A
Solution: What is Sin(B–A) equal to, when B=270 degrees and A is an acute angle
Problem 2: ECE Board April 1999
If sec2 A is 5/2, the quantity 1 – sin2 A is equivalent to?
A. 2.5
B. 1.5
C. 0.4
D. 0.6
Answer: Option C
Solution: If sec^2A is 5/2, the quantity 1 – sin^2A is equivalent to
Problem 3: ECE Board April 1999
(cos A)4 – (sin A)4 is equal to ______.
A. cos 4A
B. cos 2A
C. sin 2A
D. sin 4A
Answer: Option B
Solution: What is (cos A)^4 – (sin A)^4 equal to?
Problem 4: ECE Board April 1999
Of what quadrant is A, if sec A is positive and csc A is negative?
A. IV
B. II
C. III
D. I
Answer: Option A
Solution: Of what quadrant is A, if sec A is positive and csc A is negative?
Problem 5: ME Board October 1996
Angles are measured from the positive horizontal axis, and the positive direction is counterclockwise. What are the values of sin B and cos B in the 4th quadrant?
A. sin B > 0 and cos B < 0
B. sin B < 0 and cos B < 0
C. sin B > 0 and cos B > 0
D. sin B < 0 and cos B > 0
Answer: Option D
Solution: What are the values of sinB and cosB in the 4th quadrant?
Problem 6: ECE Board November 1998
Csc 520° is equal to
A. cos 20°
B. csc 20°
C. tan 45°
D. sin 20°
Answer: Option B
Solution: CSC 520° is equal to
Problem 7: ECE Board April 1993
Solve for θ in the following equation: Sin 2θ = cos θ
A. 30°
B. 45°
C. 60°
D. 15°
Answer: Option A
Solution: Solve for θ in the following equation: sin 2θ = cosθ
Problem 8: CE Board November 1993
If sin 3A = cos 6B, then
A. A + B = 90°
B. A + 2B = 30°
C. A + B = 180°
D. None of these
Answer: Option B
Solution: If sin 3A = cos 6B, then
Problem 9: EE Board October 1996
Solve for x, if tan 3x = 5 tan x.
A. 20.705°
B. 30.705°
C. 35.705°
D. 15.705°
Answer: Option A
Solution: Solve for x, if tan3x=5tanx
Problem 10: EE Board October 1997
If sin x cos x + sin 2x = 1, what are the values of x?
A. 32.2°, 69.3°
B. – 20.67°, 69.3°
C. 20.90°, 69.1°
D. – 32.2°, 69.3°
Answer: Option C
Solution: If sinxcosx + sin2x = 1, what are the values of x?
Problem 11: EE Board April 1997
Solve for G is csc (11G – 16 degrees) = sec (5G + 26 degrees).
A. 7 degrees
B. 5 degrees
C. 6 degrees
D. 4 degrees
Answer: Option B
Solution: Solve for G if csc (11G – 16 degrees) = sec (5G + 26 degrees)
Problem 12: EE Board April 1992
Find the value of A between 270° and 360° if sin 2 A – sin A = 1.
A. 300°
B. 320°
C. 310°
D. 330°
Answer: Option D
Solution: Find the value of A between 270° and 360° if sin^2A – sinA=1
Problem 13: CE Board November 1993
If cos 65° + cos 55° = cos θ, find the θ in radians.
A. 0.765
B. 0.087
C. 1.213
D. 1.421
Answer: Option B
Problem 14: CE Board November 1992
Find the value of sin (arc cos 15/17 ).
A. 8/11
B. 8/19
C. 8/15
D. 8/17
Answer: Option D
Solution: Find the value of sin(arc cos 15/17)
Problem 15: EE Board October 1991
The sine of a certain angle is 0.6, calculate the cotangent of the angle.
A. 4/3
B. 5/4
C. 4/5
D.3/4
Answer: Option A
Solution: Calculate the cotangent of the angle
Problem 16: EE Board March 1998
If sec 2A = (1/sin 13A), determine the angle of A in degrees.
A. 5°
B. 6°
C. 3°
D. 7°
Answer: Option B
Solution: If sec 2A=1/sin13A , determine the angle of A in degrees
Problem 17: CE Board November 1992
If tan x = 1/2, tan y = 1/3, what is the value of tan (x + y)?
A. 1/2
B. 1/6
C. 2
D. 1
Answer: Option D
Solution: If tan x=1/2, tan y=1/3, what is the value of tan (x+y)?
Problem 18: CE Board November 1993
Find the value of y in the given: y = (1 + cos 2θ) tan θ.
A. sin θ
B. cos θ
C. sin 2θ
D. cos 2θ
Answer: Option C
Problem 19: CE Board May 1992
Find the value of (sinθ + cosθtanθ)/ cosθ
A. 2 sin θ
B. 2 cos θ
C. 2 tan θ
D. 2 cot θ
Answer: Option C
Problem 20: ME Board April 1996
Simplify the equation sin2 θ (1 + cot2 θ)
A. 1
B. sin2 θ
C. sin2 θ sec2 θ
D. sec2 θ
Answer: Option A
Solution: Simplify the equation sin^2θ(1+cot^2 θ)
Problem 21: ME Board October 1995
Simplify the expression sec θ – (sec θ) sin2 θ
A. cos2 θ
B. cos θ
C. sin2 θ
D. sin θ
Answer: Option B
Problem 22: ME Board April 1998
Arc tan [2 cos (arc sin [(31/2) / 2]) is equal to
A. π/3
B. π/4
C. π/16
D. π/2
Answer: Option B
Problem 23: EE Board October 1992
Evaluate arc cot [2cos (arc sin 0.5)]
A. 30°
B. 45°
C. 60°
D. 90°
Answer: Option A
Solution: Evaluate arc cot (2cos (arc sin 0.5))
Problem 24: ECE Board March 1996
Solve for x in the given equation: Arc tan (2x) + arc tan (x) = π/4
A. 0.149
B. 0.281
C. 0.421
D. 0.316
Answer: Option B
Solution: Solve for x in the given equation: Arctan (2x)+arctan(x)=π/4
Problem 25: EE Board March 1998
Solve for x in the equation: arc tan (x + 1) + arc tan (x – 1) = arc tan (12).
A. 1.5
B. 1.34
C. 1.20
D. 1.25
Answer: Option B
Solution: Solve for x in the equation: arc tan(x+1)+arctan (x – 1)=arctan(12)
Problem 26: ECE Board November 1998
Solve for A for the given equation cos2 A = 1 – cos2 A.
A. 45 or 125, 225 or 335 degrees
B. 45 or 125, 225 or 315 degrees
C. 45 or 135, 225 or 315 degrees
D. 45, 150, 220 or 315 degrees
Answer: Option C
Solution: Solve for A for the given equation cos^2A = 1 – cos^2A.
Problem 27: ECE Board April 1991
Evaluate the following: (sin0°+sin1°+sin2°+…+sin89°+sin90°)/(cos0°+cos1°+cos2°+…+cos89°+cos90°)
A. 1
B. 0
C. 45.5
D. 10
Answer: Option A
Solution: Evaluate (sin0°+sin1°+sin2°+…+sin89°+sin90°)/(cos0°+cos1°+cos2°+…+cos89°+cos90°)
Problem 28: ECE Board April 1991
Simplify the following: ((cos A+cos B)/(sin A-sin B) + (sin A+sin B)/(cos A-cos B))
A. 0
B. sin A
C. 1
D. cos A
Answer: Option A
Solution: Simplify ((cos A+cos B)/(sin A-sin B) + (sin A+sin B)/(cos A-cos B))
Problem 29: ECE Board April 1991
Evaluate: (2sin θ cos θ-cosθ)/(1-sin θ+sin2 θ-cos2 θ)
A. sin θ
B. cos θ
C. tan θ
D. cot θ
Answer: Option D
Solution: Evaluate: (2sinθ cosθ – cosθ)/(1 – sinθ+sin^2θ-cos^2θ)
Problem 30: ECE Board April 1994
Solve for the value of “A” when sin A = 3.5x and cos A = 5.5x.
A. 32.47°
B. 33.68°
C. 34.12°
D. 35.21°
Answer: Option A
Solution: Solve for the value of “A” when sinA = 3.5x and cosA = 5.5x
Problem 31: ECE Board November 1996
If sin A = 2.511x, cos A = 3.06x and sin 2A = 3.939x, find the value of x?
A. 0.265
B. 0.256
C. 0.562
D. 0.625
Answer: Option B
Solution: If sinA = 2.511x, cosA = 3.06x and sin 2A = 3.939x, find the value of x?
Problem 32: CE Board May 1994
If coversed sin θ = 0.134, find the value of θ.
A. 30°
B. 45°
C. 60°
D. 90°
Answer: Option C
Problem 33: ME Board April 1991
A man standing on a 48.5 meter building high, has an eyesight height of 1.5 m from the top of the building, took a depression reading from the top of another nearby building and nearest wall, which are 50° and 80° respectively. Find the height of the nearby building in meters. The man is standing at the edge of the building and both buildings lie on the same horizontal plane.
A. 39.49
B. 35.50
C. 30.74
D. 42.55
Answer: Option A
Problem 34: ECE Board April 1998
Points A and B, 1000 m apart are plotted on a straight highway running East and West. From A, the bearing of a tower C is 32° W of N and from B the bearing of C is 26° N of E. Approximate the shortest distance of tower C to the highway.
A. 364 m
B. 374 m
C. 384 m
D. 394 m
Answer: Option B
Solution: Approximate the shortest distance of tower C to the highway
Problem 35: ECE Board November 1998
Two triangles have equal bases. The altitude of one triangle is 3 units more than its base and the altitude of the other triangle is 3 units less than its base. Find the altitudes, if the areas of the triangles differ by 21 square units.
A. 6 and 12
B. 3 and 9
C. 5 and 11
D. 4 and 10
Answer: Option D
Solution: Find the altitudes, if the areas of the triangles differ by 21
Problem 36: GE Board August 1994
A ship started sailing S 42°35’ W at the rate of 5kph. After 2 hours, ship B started at the same port going N 46°20’W at the rate of 7 kph. After how many hours will the second ship be exactly north of ship A?
A. 3.68
B. 4.03
C. 5.12
D. 4.83
Answer: Option B
Solution: how many hours will the second ship be exactly north of ship A?
Problem 37: ME Board April 1993
An aerolift airplane can fly at an airspeed of 300 mph. If there is a wind blowing towards the cast at 50mph, what should be the plane’s compass heading in order for its course to be 30°? What will be the plane’s ground speed if it flies in this course?
A. 19.7, 307.4 mph
B. 20.1, 309.4 mph
C. 21.7, 321.8 mph
D. 22.3, 319.2 mph
Answer: Option C
Solution: What will be the plane’s ground speed if it flies in this course?
Problem 38: ECE Board April 1998
A man finds the angle of elevation of the top of a tower to be 30°. He walks 85 m nearer the tower and finds its angle of elevation to be 60°. What is the height of the tower?
A. 76.31 m
B. 73.31 m
C. 73.16 m
D. 73.61 m
Answer: Option D
Solution: What is the height of the tower?
Problem 39: ECE Board April 1994
A pole casts a shadow 15 m long when the angle of elevation of the sun is 61°. If the pole is leaned 15° from the vertical directly towards the sun, determine the length of the pole.
A. 54.23 m
B. 48.23 m
C. 42.44 m
D. 46.21 m
Answer: Option A
Solution: Determine the length of the pole
Problem 40: ME Board November 1994
When supporting a pole is fastened to it 20 feet from the ground 15 feet from the pole. Determine the length of the wire and the angle it makes with the pole.
A. 24 ft, 53.13°
B. 24 ft, 36.87°
C. 24 ft, 53.13°
D. 25 ft, 36.87°
Answer: Option D
Solution: Determine the length of the wire and the angle it makes with the pole
Problem 41: CE Board November 1997
The angle of elevation of the top of tower B from the top of tower A is 28° and the angle of the elevation of the top of tower A from the base of tower B is 46°. The two towers lie in the same horizontal plane. If the height of tower B is 120 m, find the height of tower A.
A. 66.3 m
B. 79.3 m
C. 87.2 m
D. 90.7 m
Answer: Option B
Solution: If the height of tower B is 120 m, find the height of tower A
Problem 42: CE Board November 1997
Points A and B are 100 m apart and are of the same elevation as the foot of a building. The angles of elevation of the top of the building from points A and B are 21° and 32° respectively. How far is A from the building in meters?
A. 259.28
B. 265.42
C. 271.64
D. 277.29
Answer: Option A
Problem 43: ECE Board November 1991
The captain of a ship views the top of a lighthouse at an angle of 60° with the horizontal at an elevation of 6 meters above sea level. Five minutes later, the same captain of the ship views the top of the same lighthouse at an angle of 30° with the horizontal. Determine the speed of the ship if the lighthouse is known to be 50 meters above sea level.
A. 0.265 m/sec
B. 0.155 m/sec
C. 0.169 m/sec
D. 0.210 m/sec
Answer: Option C
Solution: Determine the speed of the ship
Problem 44: ME Board April 1997
An observer wishes to determine the height of a tower. He takes sights at the top of the tower from A and B, which are 50 feet apart, at the same elevation on a direct line with the tower. The vertical angle at point A is 30° and at point B is 40°. What is the height of the tower?
A. 85.60 feet
B. 92.54 feet
C. 110.29 feet
D. 143.97 feet
Answer: Option B
Solution: What is the height of the tower?
Problem 45: ME Board April 1993
A PLDT tower and a monument stand on a level plane. The angles of depression of the top and bottom of the monument viewed from the top of the PLDT tower at 13° and 35°, respectively. The height of the tower is 50 m. Find the height of the monument.
A. 29.13 m
B. 30.11 m
C. 32.12 m
D. 33.51 m
Answer: Option D
Solution: Find the height of the monument stand on a level plane
Problem 46: ECE Board November 1998
If an equilateral triangle is circumscribed about a circle of radius 10 cm, determine the side of the triangle.
A. 34.64 cm
B. 64.12 cm
C. 36.44 cm
D. 32.10 cm
Answer: Option A
Problem 47: EE Board October 1997
The two legs of a triangle are 300 and 150 m each, respectively. The angle opposite the 150 m side is 26°. What is the third side?
A. 197.49 m
B. 218.61 m
C. 341.78 m
D. 282.15 m
Answer: Option C
Solution: What is the third side of the triangle?
Problem 48: EE Board October 1997
The sides of a triangular lot are 130 m., 180 m and 190 m. The lot is to be divided by a line bisecting the longest side and drawn from the opposite vertex. Find the length of the line.
A. 120 m
B. 130 m
C. 125 m
D. 128 m
Answer: Option C
Solution: Find the length of the line bisecting the longest side of a triangular lot
Problem 49: EE Board October 1997
The sides of a triangle are 195, 157 and 210, respectively. What is the area of the triangle?
A. 73,250 sq. units
B. 10,250 sq. units
C. 14,586 sq. units
D. 11,260 sq. units
Answer: Option C
Solution: Given three sides, What is the area of the triangle?
Problem 50:ECE Board April 1998
The sides of a triangle are 8, 15 and 17 units. If each side is doubled, how many square units will the area of the new triangle be?
A. 240
B. 420
C. 320
D. 200
Answer: Option A
Solution: How many square units will the area of the new triangle be?
Online Questions and Answers in Plane Trigonometry Series
Following is the list of multiple choice questions in this brand new series:
Online Questions and Answers in Spherical Trigonometry
Mathematics Board Examination Mastery | Math Engineering Pre-Board
P inoyBIX educates thousands of reviewers and students a day in preparation for their board examinations. Also provides professionals with materials for their lectures and practice exams. Help me go forward with the same spirit.
“Will you subscribe today via YOUTUBE?”
TIRED OF ADS?
- Become Premium Member and experienced complete ads-free content browsing.
- Full Content Access to Premium Solutions Exclusive for Premium members
- Access to PINOYBIX FREEBIES folder
- Download Reviewers and Learning Materials Free
- Download Content: You can see download/print button at the bottom of each post.
PINOYBIX FREEBIES FOR PREMIUM MEMBERSHIP:
- CIVIL ENGINEERING REVIEWER
- CIVIL SERVICE EXAM REVIEWER
- CRIMINOLOGY REVIEWER
- ELECTRONICS ENGINEERING REVIEWER (ECE/ECT)
- ELECTRICAL ENGINEERING & RME REVIEWER
- FIRE OFFICER EXAMINATION REVIEWER
- LET REVIEWER
- MASTER PLUMBER REVIEWER
- MECHANICAL ENGINEERING REVIEWER
- NAPOLCOM REVIEWER
- Additional upload reviewers and learning materials are also FREE
FOR A LIMITED TIME
If you subscribe for PREMIUM today!
You will receive an additional 1 month of Premium Membership FREE.
For Bronze Membership an additional 2 months of Premium Membership FREE.
For Silver Membership an additional 3 months of Premium Membership FREE.
For Gold Membership an additional 5 months of Premium Membership FREE.
Join the PinoyBIX community.

