Problem Statement:
Two pound of an ideal gas undergoes an isentropic process from 93.5 psig and a volume of 0.6 cu. ft to a final volume of 3.6 cu. ft. If cp = 0.124 and cv = 0.093 BTU/lb.°R, what are (a) T2 (b) P2 (c) ∆H and (d) W.Course: Thermodynamics
TOPIC: Processes of Ideal Gas SUBTOPIC: Isentropic Process DEFINITION: Isentropic Process is a reversible adiabatic process. Adiabatic simply means no heat. A reversible adiabatic is one of constant entropy.Problem Answer:
a.) T2 = 109.3639°R b.) P2 = 7.9639 psia c.) ∆H = -24. 9473 BTu d.) W = 18.7123 BTuView Solution:
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