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Review: Problem Solving in Isentropic Process 01

(Last Updated On: December 18, 2017)

Review: Problem Solving in Isentropic Process 01

Problem Statement:

Two pound of an ideal gas undergoes an isentropic process from 93.5 psig and a volume of 0.6 cu. ft to a final volume of 3.6 cu. ft. If cp = 0.124 and cv = 0.093 BTU/lb.°R, what are (a) T2 (b) P2 (c) ∆H and (d) W.

Course: Thermodynamics

TOPIC: Processes of Ideal Gas

SUBTOPIC: Isentropic Process

DEFINITION: Isentropic Process is a reversible adiabatic process. Adiabatic simply means no heat. A reversible adiabatic is one of constant entropy.

Problem Answer:

a.) T2 = 109.3639°R b.) P2 = 7.9639 psia c.) ∆H = -24. 9473 BTu d.) W = 18.7123 BTu

View Solution:
Review: Problem Solving in Isentropic Process 01
Review: Problem Solving in Isentropic Process 01

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