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# Review: Problem Solving in Isometric Process 03

#### Problem Statement:

There are 2.33 kg of gas for which R = 377 J/kg.ยฐK and k = 1.25, that undergo a nonflow constant volume process from P1 = 657.8 kPa and T1 = 66ยฐC to P2 = 1745 kPa. During the process the gas is internally stirred and there are also added 108.25 kJ of heat. Determine (a) T2 (b) the work input and (c) the change of entropy.
##### Course: Thermodynamics
TOPIC: Processes of Ideal Gas SUBTOPIC: Isometric Process DEFINITION: An Isometric Process is a reversible constant volume process. A constant volume process maybe reversible or irreversible.

a.) T2 = 907.97ยฐK b.) Wn = -1890.38 kJ c.) โS = 3.46 kJ/ยฐK
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