Problem Statement:
A perfect gas has a value of R = 766.54 ft.lbf/lbm – °R and k = 1.26. If 30 Btu are added to 5 lbm of this gas at constant volume when the initial temperature is 95°F, find (a) T2 (b) Change in H (c) Change in S (d) Change in U (e) Work for a non flow process.Course: Thermodynamics
TOPIC: Processes of Ideal Gas SUBTOPIC: Isometric Process DEFINITION: An Isometric Process is a reversible constant volume process. A constant volume process maybe reversible or irreversible.Problem Answer:
a.) T2 = 556.22°R b.) ∆H = 41.97 BTU c.) ∆S = 0.049 BTu/°R d.) ∆U = 30 BTu e.) W = 0View Solution:
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Bakit ung mass po biglang naging 10lbm? E sabi sa problem 30 Btu are added to 5lbm??
ows, thanks sa feedback hindi ko napansin. iba pala ung given na binigay ko sa quiz that time.
Salamat po engr. Hehe!