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Review: Problem Solving in IsometricProcess 01

(Last Updated On: December 18, 2017)

Review: Problem Solving in IsometricProcess 01

Problem Statement:

A perfect gas has a value of R = 766.54 ft.lbf/lbm – °R and k = 1.26. If 30 Btu are added to 5 lbm of this gas at constant volume when the initial temperature is 95°F, find (a) T2 (b) Change in H (c) Change in S (d) Change in U (e) Work for a non flow process.

Course: Thermodynamics

TOPIC: Processes of Ideal Gas

SUBTOPIC: Isometric Process

DEFINITION: An Isometric Process is a reversible constant volume process. A constant volume process maybe reversible or irreversible.

Problem Answer:

a.) T2 = 556.22°R b.) ∆H = 41.97 BTU c.) ∆S = 0.049 BTu/°R d.) ∆U = 30 BTu e.) W = 0

View Solution:
Review: Problem Solving in IsometricProcess 01

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