#### Problem Statement: EE Board October 1997

If dy=x^2 dx; what is the equation of y in terms of x if the curve passes through (1, 1).

- A. x^2 – 3y + 3 = 0
- B. x^3 – 3y + 2 = 0
- C. x^3 + 3y^2 + 2 = 0
- D. 2y + x^3 + 2 = 0

#### Problem Answer:

The equation of y in terms of x is **x^3 – 3y + 2 = 0**

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