# Solution: If dy=x^2 dx; what is the equation of y in terms of x if the curve passes through (1, 1)

(Last Updated On: January 22, 2020) #### Problem Statement: EE Board October 1997

If dy=x^2 dx; what is the equation of y in terms of x if the curve passes through (1, 1).

• A. x^2 – 3y + 3 = 0
• B. x^3 – 3y + 2 = 0
• C. x^3 + 3y^2 + 2 = 0
• D. 2y + x^3 + 2 = 0

The equation of y in terms of x is x^3 – 3y + 2 = 0

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