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Solution: Find the inverse Laplace transform of ( 2s – 18 ) / ( s^2 + 9 )

(Last Updated On: March 13, 2019)

Find the inverse Laplace transform of ( 2s – 18 ) / ( s^2 + 9 ) as a function of x.

Problem Statement:

Find the inverse Laplace transform of ( 2s – 18 ) / ( s^2 + 9 ) as a function of x.

Problem Answer:

The inverse Laplace transform is equal to 2 cos 3x – 6 sin 3x.

View Solution:
Solution: Find the inverse Laplace transform of ( 2s – 18 ) / ( s^2 + 9 )

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Solution: Find the inverse Laplace transform of ( 2s – 18 ) / ( s^2 + 9 )
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