#### Problem Statement:

Find the equation whose roots are twice the roots of the equation x3 – 6×2 + 11x – 6 = 0.

#### Problem Answer:

The equation whose roots are twice the roots of the equation x3 – 6×2 + 11x – 6 = 0 is **x3 – 12×2 + 44x – 48 = 0**.

Solution:

### Latest Problem Solving in Quadratic Equation, Binomial Theorem and Logarithms

div.feedburnerFeedBlock ul li {background: #E2F0FD;

list-style-type: none;

margin:0 0 5px 0px;

padding:5px 5px 5px 10px !important;

border: 1px solid #0080ff;

border-radius:8px;

-moz-border-radius:8px;

-webkit-border-radius:8px;

}

div.feedburnerFeedBlock ul li:hover {

background:#ffffff;

}

div.feedburnerFeedBlock ul li a{

color:#ffffff;

text-decoration:none;

}

div.feedburnerFeedBlock ul li a:hover {

text-decoration: underline;

color: #000000;

}

div #creditfooter{

display: none;

}

More Questions in: Quadratic Equation, Binomial Theorem and Logarithms