#### Problem Statement: ME Board October 1996

Solve the simultaneous equations:

2x^2 – 3y^2 = 6

3x^2 + 2y^2 = 35

- A.
- B. x = 3 or -3, y = -2 or 1
- C. x = 3 or -3, y = -2 or -1
- D. x = 3 or -3, y = 2 or -3

#### Problem Answer:

The value of **x is equal to ±3 ** while **y is equal to ±2**.

Solution:

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