# Solution: Find the value of A in the equation: (x^2+4x+10)/(x^3+2x^2+5x) = A/x+B(2x+2)/(x^2+2x+5)+C/(x^2+2x+5)

(Last Updated On: January 23, 2020)

#### Problem Statement: CE Board May 1996

Find the value of A in the equation: (x^2+4x+10)/(x^3+2x^2+5x) = A/x+B(2x+2)/(x^2+2x+5)+C/(x^2+2x+5).

• A. -2
• B. 1/2
• C. -1/2
• D. 2

A is equal to 2.

View Solution:

#### Latest Problem Solving in Fundamentals in Algebra

More Questions in: Fundamentals in Algebra

#### Online Questions and Answers in Fundamentals in Algebra Series

Help Me Makes a Difference!

 P inoyBIX educates thousands of reviewers/students a day in preparation for their board examinations. Also provides professionals with materials for their lectures and practice exams. Help me go forward with the same spirit. “Will you make a small gift today via GCASH?” +63 966 459 6474 Option 1 : \$1 USD Option 2 : \$3 USD Option 3 : \$5 USD Option 4 : \$10 USD Option 5 : \$25 USD Option 6 : \$50 USD Option 7 : \$100 USD Option 8 : Other Amount

#### GEAS Solution

Dynamics problem Economics problem Physics problem Statics problem Strength problem Thermodynamics problem

#### Questions and Answers in GEAS

Engineering Economics Engineering Laws and Ethics Engineering Management Engineering Materials Engineering Mechanics General Chemistry Giancoli Physics Physics Strength of Materials Thermodynamics