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# Solution: What is the equation of the normal to the curve x^2+y^2=25 at (4, 3)?

#### Problem Statement: CE Board May 1995

What is the equation of the normal to the curve x^2+y^2=25 at (4, 3)?

Note: The slope of the line normal to the curve at the given point is equal to the negative of the reciprocal of the slope of the given curve.

• A. 5x + 3y = 0
• B. 3x โ 4y = 0
• C. 3x + 4y = 0
• D. 5x โ 3y = 0

The equation of the normal to the curve is equal to 3x โ 4y = 0

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