Problem Statement: CE Board May 1995
What is the equation of the normal to the curve x^2+y^2=25 at (4, 3)?
Note: The slope of the line normal to the curve at the given point is equal to the negative of the reciprocal of the slope of the given curve.
- A. 5x + 3y = 0
- B. 3x – 4y = 0
- C. 3x + 4y = 0
- D. 5x – 3y = 0
The equation of the normal to the curve is equal to 3x – 4y = 0
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