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Solution: What is the equation of the normal to the curve x^2 + y^2 = 25 at (4, 3)?

(Last Updated On: December 8, 2017)

What is the equation of the normal to the curve x^2 + y^2 = 25 at (4, 3)?

Problem Statement: CE Board May 1995

What is the equation of the normal to the curve x^2 + y^2 = 25 at (4, 3)?

Note: The slope of the line normal to the curve at the given point is equal to the negative of the reciprocal of the slope of the given curve.

  • A. 5x + 3y = 0
  • B. 3x – 4y = 0
  • C. 3x + 4y = 0
  • D. 5x – 3y = 0

Problem Answer:

The equation of the normal to the curve is equal to 3x – 4y = 0

Solution:

Solution: What is the equation of the normal to the curve x^2 + y^2 = 25 at (4, 3)?

Latest Problem Solving in Differential Calculus (LIMITS & DERIVATIVES)

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