Uncategorized

Solution: Find the slope of the ellipse x^2+4y^2–10x–16y+5 = 0 at the point where y = 2+8^0.5 and x = 7

Find the slope of the ellipse x^2+4y^2–10x–16y+5 = 0 at the point where y = 2+8^0.5 and x = 7.

Problem Statement: CE Board May 1996

Find the slope of the ellipse x^2+4y^2–10x–16y+5 = 0 at the point where y = 2+8^0.5 and x = 7.

  • A. -0.1463
  • B. -0.1538
  • C. -0.1654
  • D. -0.1768

Problem Answer:

The slope of the ellipse is equal to -0.1768

Solution:

Latest Problem Solving in Differential Calculus (LIMITS & DERIVATIVES)

div.feedburnerFeedBlock ul li {background: #E2F0FD;
list-style-type: none;
margin:0 0 5px 0px;
padding:5px 5px 5px 10px !important;
border: 1px solid #0080ff;
border-radius:8px;
-moz-border-radius:8px;
-webkit-border-radius:8px;
}

div.feedburnerFeedBlock ul li:hover {
background:#ffffff;
}

div.feedburnerFeedBlock ul li a{
color:#ffffff;
text-decoration:none;
}

div.feedburnerFeedBlock ul li a:hover {
text-decoration: underline;
color: #000000;
}
div #creditfooter{
display: none;
}

More Questions in: Differential Calculus (LIMITS & DERIVATIVES)

Online Questions and Answers in Differential Calculus (LIMITS & DERIVATIVES)

Leave a Reply

Your email address will not be published. Required fields are marked *