
This is the Multiple Choice Questions Part 6 of the Series in AC Circuits as one of the Electrical Engineering topic. In Preparation for the REE Board Exam make sure to expose yourself and familiarize in each and every questions compiled here taken from various sources including but not limited to past Board Exam Questions in Electrical Engineering field, Electrical Engineering Books, Journals and other Electrical Engineering References.
Continue Practice Exam Test Questions Part 6 of the Series
SERIES CIRCUITS
Choose the letter of the best answer in each question.
⇐ MCQ in AC Circuits Part 5 | REE Board Exam
251. A circuit draws a current of (3 – j8) A from a source of (100 + j37) V. Find the true power of the circuit.
A. 4 W
B. 596 W
C. 300 W
D. 296 W
252. A resistor and a coil are connected in series with a voltage source. If the voltage across the coil is 10 sin (866t + 70°) V and the current flowing through the resistor is 2 cos (866t – 80°) A, what is the resistance of the coil?
A. 4.92 Ω
B. 2.5 Ω
C. 5 Ω
D. 4.33 Ω
Answer: Option B
Solution:
253. A coil has a resistance of 6 ohms and an inductance of 0.02 H. When a noninductive resistor is connected in series with the coil, the current drawn when connected to 220 V DC source is equal to the current drawn by the coil alone across a 220 V, 60 Hz source. Determine the resistance of the non-inductive resistor.
A. 3.63 Ω
B. 6.39 Ω
C. 3.69 Ω
D. 3.96 Ω
254. A series RL circuit has L = 0.02 H and an impedance of 17.85 Ω. When a sinusoidal voltage is applied, the current lags the voltage by 63.5°. What is the value of the angular frequency?
A. 400 rad/sec
B. 500 rad/sec
C. 600 rad/sec
D. 800 rad/sec
255. A 50 Ω resistance is connected in series with a coil having 25 Ω resistance and 150 mH inductance. The circuit is connected to a voltage source of 200 sin ωt. Calculate the instantaneous current.
A. 2.9 sin ωt
B. 1.7 sin (ωt + 37°)
C. 2.1 sin (ωt – 37°)
D. 5.11 sin (ωt – 37°)
256. A coil having a resistance of 25 Ω and an inductance of 150 mH is connected in series with an 80 μF capacitor across a voltage source of 200 sin 377t. What is its instantaneous current?
A. 5.84 cos (377t – 43°)
B. 5.84 sin 377t
C. 5.84 sin (377t + 43°)
D. 5.84 sin (377t – 43°)
257. A coil with a 15 Ω resistance is connected in series with a capacitor. At 60 Hz source, the impedance is measured at 15 + j11.27 Ω while in 30 Hz source it is measured as 15 – j7.24 Ω. Calculate the inductance of the coil.
A. 52.7 mH
B. 65.8 mH
C. 41.2 mH
D. 11.27 mH
258. An impedance coil has a resistance and inductance of 20 ohms and 0.05 H respectively. What value of dc voltage can be applied to the coil in order that it will take the same power from a 220 V 60 Hz mains?
A. 188 V
B. 220 V
C. 160 V
D. 120 V
259. A ½ HP, 110 V, 60 Hz, single-phase induction motor has an efficiency of 88% and a power factor of 0.707 lagging at rated load. This motor is to be connected temporarily on a 220 V, 60 Hz line. Determine the resistance required to be placed in series with the motor in order to prevent the machine from experiencing overcurrent?
A. 25.2 ohms
B. 23.5 ohms
C. 19.5 ohms
D. 27.6 ohms
Answer: Option B
Solution:
260. Two coils A and B known to have the same resistance are connected in series across a 110 V, 60 cycle line. The current and power delivered by the source are respectively 4.1 A and 300 W. If the voltage across coil A is twice that across coil B, calculate the inductance of coil B.
A. 8.63 mH
B. 7.36 mH
C. 9.02 mH
D. 4.49 mH
261. The total voltage in a series RL circuit ____ the current by an angle ____.
A. lags, of 90°
B. lags, between 0° and 90°
C. leads, between 0° and 90°
D. leads, between 90° and 180°
Answer: Option C
Solution:
262. In a series RL circuit, the inductor current ____ the resistor current.
A. lags
B. is equal
C. leads
D. is negative
Answer: Option A
Solution:
263. The impedance triangle is similar to the ____ triangle with the resistance phasor in place of the ____.
A. current, resistor current
B. current, resistor voltage
C. voltage, impedance
D. voltage, resistor voltage
Answer: Option C
Solution:
264. In the impedance triangle the inductive reactance and impedance phasor are analogous to the ____ and ____ phasor respectively in the voltage triangle.
A. inductive voltage, total voltage
B. inductive current, total current
C. inductive voltage, resistive current
D. inductive current, resistive current
Answer: Option A
Solution:
265. In a series RL circuit, phasor diagram, total voltage may be represented by the ____ phasor and the resistor voltage may be represented by the ____ voltage.
A. current, voltage
B. impedance, resistance
C. current, resistance
D. impedance, inductance
Answer: Option B
Solution:
266. The phase angle of a series RL circuit is the angle between the ____ phasor and the ____ phasor.
A. resistance, inductive reactance
B. resistance, impedance
C. inductive reactance, impedance
D. none of the above
Answer: Option B
Solution:
267. The phase angle of a series RL circuit may be computed ____ as ____ or ____.
A. cos-1 R/XL, sin-1 XL/R, tan-1 R/Z
B. cos-1 R/Z, sin-1 XL/R, tan-1 R/XL
C. cos-1 Z/XL, sin-1 R/Z, tan-1 XL/R
D. cos-1 R/Z, sin-1 XL/Z, tan-1 XL/R
Answer: Option D
Solution:
268. In the circuit of figure shown the effective value of the resistor voltage is ____ volts.

A. 5 √2
B. 5
C. 5/√2
D. 10
Answer: Option A
Solution:
269. A(n) ____ stores and returns energy to a circuit while a(n) ____ dissipates energy.
A. resistor, impedance
B. resistor, inductor
C. inductor, resistor
D. inductor, reactance
Answer: Option C
Solution:
270. For an RL circuit, the power factor cannot be less than ____ or greater than ____.
A. 0, 1
B. 1, 0
C. 0, -1
D. –1, 0
Answer: Option A
Solution:
271. The voltage across a capacitor ____ the current through it by ____.
A. lags, 45°
B. lags, 90°
C. leads, 0°
D. leads, 90°
Answer: Option B
Solution:
272. If the resistance in a series RC circuit is increased the magnitude of thephase angle
A. increases
B. remains the same
C. decreases
D. changes to an indeterminate manner
Answer: Option C
Solution:
273. In a series RC circuit, the current ____ the total voltage by an angle.
A. lags, of 45°
B. lags of 0°
C. leads, between 0° and 90°
D. leads, of 90°
Answer: Option C
Solution:
274. The resistance phasor for a series RC circuit points to the right. The capacitive reactance phasor points ____ while the diagonal of the rectangle having there two phasors as sides represents the ____.
A. up, impedance
B. left, current
C. down, impedance
D. up, total voltage
Answer: Option C
Solution:
275. The phase angle for a series RC circuit is defined as the angle between the ____ and the ____ phasors.
A. current, resistance voltage
B. current, total voltage
C. resistance voltage, capacitor voltage
D. R, XC
Answer: Option B
Solution:
276. The phase angle for a series RC circuit may be computed as the angle between the ____ and the ____ phasors.
A. resistance, impedance
B. resistance, reactance
C. resistance, impedance
D. none of these
Answer: Option A
Solution:
277. If a series RC circuit with 10 ohms and XC = 10 ohms carries a current of 1 ampere effective value the resistor voltage is ____ volts effective and the capacitor voltage is ____ volts effective.
A. 10/√2 , 10/√2
B. 10, 10
C. 10√2 , 10√2
D. 5, 10
Answer: Option B
Solution:
278. The power dissipated in a series RL circuit with R =10 ohms and XC = 10 ohms carrying an effective current of 3 amps is _____ watts.
A. 30
B. 30√2
C. 90
D. 90√2
Answer: Option C
Solution:
279. The magnitude of the power factor of an RC circuit with R = 10 ohms, XC = 10 ohms. I = 2 amp effective is ______.
A. 1
B. 0.5
C. 0.707
D. 0.02
Answer: Option C
Solution:
280. The power dissipated in the circuit shown is ____ watts.

A. 60
B. 80
C. 100
D. 120
Answer: Option D
Solution:
281. The net reactance in an RLC circuit is
A. XL
B. XC – XL
C. XC
D. XL – XC
Answer: Option D
Solution:
282. The impedance of a series RLC circuit is ______.
A. √(R2 + XL2 + XC2)
B. √(R2 + XL2 – XC2)
C. √(R2 + (XL + XC)2)
D. √(R2 + (XL – XC)2)
Answer: Option D
Solution:
283. In a series RC circuit, the voltage across the capacitor and the resistor are 60 V and 80 V respectively. The input voltage should be
A. 70∠45° V
B. 100∠-37° V
C. 105∠-42° V
D. 108∠-60° V
Answer: Option B
Solution:
284. The transient current are due to
A. voltage applied to circuit
B. resistance of the circuit
C. impedance of the circuit
D. changes in stored energy in inductance and capacitance
Answer: Option D
Solution:
285. To a highly inductive circuit, a small capacitance is added in series. The angle between voltage and current will
A. increase
B. decrease
C. remain nearly the same
D. become indeterminant
Answer: Option B
Solution:
286. In a series R-L circuit. VL ____ VR by ____ degrees.
A. lags, 45
B. lags, 90
C. leads, 90
D. leads, 45
Answer: Option C
Solution:
287. The voltage applied across an R-L circuit is equal to _____ of VR and VL.
A. arithmetic sum
B. algebraic sum
C. phasor sum
D. sum of the squares
Answer: Option C
Solution:
288. The power in an a.c. circuit is given by
A. VI cos φ
B. VI sin φ
C. I² Z
D. I² XL
Answer: Option A
Solution:
289. The p.f. of an R-C circuit is
A. often zero
B. between zero and 1
C. always unity
D. between zero and -1.0
Answer: Option B
Solution:
290. Which phasor diagram is correct for a series R-C circuit?

A. Figure 1
B. Figure 2
C. Figure 3
D. Figure 4
Answer: Option B
Solution:
291. In an R-L-C circuit, v(t) = 20 sin (314t + 5π/6) and i(t) = 10 sin (314t + 2π/3). The p.f. of the circuit is ____ and power drawn is ____ watt.
A. 0.5 lead, 200
B. 0.886 lag, 186.6
C. 0.866 lead, 173.2
D. 0.5 lag, 50
Answer: Option B
Solution:
292. The input of an a.c. circuit having p.f. of 0.8 lagging is 20 kVA. The power drawn by the circuit is ____ kW.
A. 12
B. 20
C. 16
D. 8
293. The power factor of an a.c. circuit is given by
A. cosine of the phase angle
B. tangent of the phase angle
C. the ratio R/XL
D. the ratio XL/Z
Answer: Option A
Solution:
294. In series R-L-C circuit, R = 100 Ω, XL = 300 Ω and XC = 200 Ω. The phase angle Φ of the circuit is _____ degrees.
A. 0
B. 90
C. 45
D. -45
Answer: Option C
Solution:
295. The phase angle of a series R-L-C circuit is leading if
A. XL = 0
B. R = 0
C. XC > XL
D. XC < XL
Answer: Option C
Solution:
296. In an a.c. circuit, the ratio of kW/kVA represents
A. power factor
B. load factor
C. form factor
D. diversity factor
Answer: Option A
Solution:
297. If p.f. of a circuit is unity, its reactive power is
A. a maximum
B. equal to I²R
C. zero
D. a negative quantity
Answer: Option C
Solution:
298. An R-L-C circuit has R = 10 Ω, XL = 20 Ω and XC = 30 Ω. The impedance of the circuit is given by the expression.
A. Z = 10 + j20
B. Z = 10 + j50
C. Z = 10 – j20
D. Z = -10 + j20
Answer: Option C
Solution:
299. An alternating voltage e = 200 sin 314t is applied to a device which offers an ohmic resistance of 20 Ω to the flow of current in one direction while entirely preventing the flow in the opposite direction. The average value of current will be
A. 5 A
B. 3.18 A
C. 1.57 A
D. 1.10 A
Answer: Option B
Solution:
300. A 10 mH inductor carries a sinusoidal current of 1 A rms at a frequency of 50 Hz. The average power dissipated by the inductor is
A. 0 W
B. 0.25 W
C. 0.5 W
D. 1.0 W
Answer: Option A
Solution:
⇒ MCQ in AC Circuits Part 7 | REE Board Exam
Questions and Answers in AC Circuits
Following is the list of practice exam test questions in this brand new series:
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