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# MCQ in AC Circuits Part 7 | REE Board Exam

This is the Multiple Choice Questions Part 7 of the Series in AC Circuits as one of the Electrical Engineering topic. In Preparation for the REE Board Exam make sure to expose yourself and familiarize in each and every questions compiled here taken from various sources including but not limited to past Board Exam Questions in Electrical Engineering field, Electrical Engineering Books, Journals and other Electrical Engineering References.

#### Continue Practice Exam Test Questions Part 7 of the Series

SERIES CIRCUITS

Choose the letter of the best answer in each questions.

301.ย  A circuit component that opposes the change in circuit voltage is

A.ย  resistance

B.ย  capacitance

C.ย  inductance

D.ย  all of these

Solution:

302.ย  Power loss in an electrical circuit can take place in

A.ย  inductance only

B.ย  capacitance only

C.ย  inductance and resistance

D.ย  resistance only

Solution:

303.ย  A circuit of zero lagging power factor behaves as

A.ย  an inductive circuit

B.ย  a capacitive circuit

C.ย  R-L circuit

D.ย  R-C circuit

Solution:

304.ย  In an R-L series circuit the power factor is

B.ย  lagging

C.ย  zero

D.ย  unity

Solution:

305.ย  When a sinusoidal voltage is applied across an R-L series circuit having R = XL, the phase angle will be

A.ย  90ยฐ

B.ย  45ยฐ lagging

Solution:

306.ย  Anย  acย  sourceย  havingย  voltageย  eย  =ย  110ย  sinย  (ฯtย  +ย  ฯ/3)ย  isย  connectedย  inย  anย  ac circuit. If the current drawn from the circuit varies as i = 5 sin (ฯtย  –ย  ฯ/3) the impedance of the circuit will be

A.ย  22 ฮฉ

B.ย  16 ฮฉ

C.ย  30.8ย ย  ฮฉ

D.ย  none of these

Solution:

307.ย  Which are of the following true of the circuit shown in the given figure?

1.ย  VR =ย  100โ2ย  Vย ย ย ย ย ย ย  2.ย  I = 2 Aย ย ย ย ย  3.ย  L = 0.25 H

Select the correct answer using the codes given below:

Codes:

A.ย  2 and 3

B.ย  1 and 2

C.ย  1 and 3

D.ย  1, 2 and 3

Solution:

308.ย  Theย  R-Lย  circuitย  ofย  theย  figureย  isย  fedย  fromย  aย  constantย  magnitudeย  variable frequencyย  sinusoidalย  voltageย  sourceย  vin.ย  Atย  100ย  Hz,ย  theย  Rย  andย  Lย  element each has a voltage drop Vrms. If theย  frequency of the source is changes to 50 Hz, then new voltage drop across R is

A.ย  โ(5/8) Vrms

B.ย  โ(2/3) Vrms

C.ย  โ(8/5) Vrms

D.ย  โ(3/2) Vrms

Solution:

309. Anย ac source of 200 Vrms supplies active power of 600 W and reactive power of 800 VAR. The rms current drawn from the source is

A.ย  10 A

B.ย  5 A

C.ย  3.75 A

D.ย  2.5 A

Solution:

310.ย  A square wave is fed to an R-C circuit. Then

A.ย  voltage across R is square and across C is not square

B.ย  voltage across C is square and across R is not square

C.ย  voltage across both R and C is square

D.ย  voltage across both R and C is not square

Solution:

311.ย  Theย  voltageย  phasorย  ofย  aย  circuitย  is 10โ 15ยฐ Vย  andย  theย  currentย  phasorย  is 2โ -45ยฐ A. The active and reactive powers in the circuit are

A.ย  10 W and 17.32 VAR

B.ย  5 W and 8.66 VAR

C.ย  20 W and 60 VAR

D.ย  20โ2 W andย  10โ2 VAR

Solution:

312.ย  In a two-element series circuit, the applied voltage and resultant current are respectively, v(t) = 50 + 50 sin (5 x 103 t) and i(t) = 11.2 sin (5 x 103 t + 63.4ยฐ). The nature of the elements would be

A.ย  R-L

B.ย  R-C

C.ย  L-C

D.ย  neither R, nor L, nor C

Solution:

313.ย  Aย  seriesย  circuitย  passiveย  elementsย  hasย  theย  followingย  currentย  andย  applied voltage: v = 200 sin (2,000t + 50ยฐ), i = 4 cos (2,000t + 13.2ยฐ). The circuit elements

A.ย  must be resistance and capacitance

B.ย  must be resistance and inductance

C.ย  must be inductance, capacitance and resistance

D.ย  couldย  beย  eitherย  resistanceย  andย  capacitanceย  orย  resistance,ย  inductance and capacitance

Solution:

314.ย  A two terminal black box contains one of the R-L-C elements. The black box is connected to a 220 V ac supply. The current through the source is I. When a capacitance of 0.1 F is inserted in series between the source and the box, the current through the source is 2I. The element is

A.ย  a resistance

B.ย  an inductance

C.ย  a capacitance

D.ย  it is not possible to determine the element

Solution:

315.ย  In the following circuit, i(t) under steady state is

A.ย  zero

B.ย  5

C.ย  7.07 sin t

D.ย  7.07 sin (t โ 45ยฐ)

Solution:

316.ย  The source in the circuit is a sinusoidal source. The supply voltages across various elements are marked in the figure. The input voltage is

A.ย  10 V

B.ย  5 V

C.ย  27 V

D.ย  24 V

Solution:

317.ย  In the circuit shown in the given figure, if the power consumed by the 5 ฮฉ resistor is 10 W, then the pf of the circuit is

A.ย  0.8

B.ย  0.6

C.ย  0.5

D.ย  zero

Solution:

318.ย  Inย  anย  RLย  circuit,ย  suppliedย  fromย  anย  acย  source,ย  theย  reactiveย  powerย  is proportional to the

A.ย  the average energy stored in the electric field

B.ย  the average energy stored in the magnetic field

C.ย  sum of the average energy stored in the electric field and that stored in the magnetic field

D.ย  differenceย  ofย  theย  averageย  energyย  storedย  inย  theย  electricย  fieldย  andย  that stored in the magnetic field

Solution:

319.ย  If a series RLC circuit excited by a voltage e = E sin ฯt when LC < 1/ฯ2

A.ย  current lags behind the applied voltage

B.ย  current leads the applied voltage

C.ย  current is in phase with the applied voltage

D.ย  voltage across L and C are equal

Solution:

320.ย  The current in the circuit shown is

A.ย  5 A

B.ย  10 A

C.ย  15 A

D.ย  25 A

Solution:

321.ย  In the case of the R-L-C circuit shown in the given figure, the voltage across the R, L and C would be respectively

A.ย  12 V, 16 V and 7 V or 25 V

B.ย  16 V, 12 V and 7 V or 25 V

C.ย  7 V, 16 V and 12 V

D.ย  16 V, 12 V and 25 V

Solution:

322.ย  Consider the following statements regarding the circuit shown in the figure.

If the power consumed by 5 ฮฉ resistor is 10 W then

1.ย  |I| = โ2ย  A

2.ย  the total impedance of the circuit is 5 ฮฉ

3.ย  cos ฮธ = 0.866

Which of these statements is correct?

A.ย  1 and 3

B.ย  2 and 3

C.ย  1 and 2

D.ย  1, 2 and 3

Solution:

323.ย  In an ac circuit if voltage V = (a + jb) and current I = (c + jd), then the power is given by

B.ย  ac + bd

Solution:

324.ย  The reactive power drawn from the source in the network in the given figure is

A.ย  300 VAR

B.ย  200 VAR

C.ย  100 VAR

D.ย  zero

Solution:

325.ย  Aย  seriesย  R-L-Cย  circuit,ย  consistingย  ofย  Rย  =ย  10ย  ฮฉ,ย  XLย  =ย  20ย  ฮฉ,ย  XCย  =ย  20ย  ฮฉย  is connectedย  acrossย  an ac supplyย  ofย  100ย  Vย  (rms).ย  Theย  magnitudeย  andย  phase angle (with reference to supply voltage) of the voltage across the inductive coil are respectively

A.ย  100 V, 90ยฐ

B.ย  100 V, -90ยฐ

C.ย  200 V, -90ยฐ

D.ย  200 V, 90ยฐ

Solution:

326.ย  For a capacitor in a sine wave ac circuit

A.ย  vC lags iC by 90ยฐ

B.ย  iC leads vC by 90ยฐ

C.ย  iC and vC have the same frequency

D.ย  all of these

Solution:

327.ย  In a series RC circuit,

A.ย  VC leads VR by 90ยฐ

B.ย  VC and I are in phase

C.ย  VC lags VR by 90ยฐ

D.ย  both B and C

Solution:

328.ย  In a series RC circuit,

A.ย  VC and VR are in phase

B.ย  VT and I are always in phase

C.ย  VR and I are in phase

D.ย  VR leads I by 90ยฐ

Solution:

329.ย  When the frequency of the applied voltage increases in a series RC circuit

A.ย  the phase angle, ฮธT, becomes more negative

B.ย  ZT increases

C.ย  ZT decreases

D.ย  both A and B

Solution:

330.ย  Inductive reactance, XL

A.ย  applies only to non-sinusoidal waveforms or dc

B.ย  applies only to sine waves

C.ย  applies to either sinusoidal or non-sinusoidal waveforms

D.ย  is inversely proportional to frequency

Solution:

331.ย  For an inductor in a sine wave ac circuit

A.ย  VT leads iL by 90ยฐ

B.ย  VT lags iL by 90ยฐ

C.ย  VT and iL are in phase

D.ย  none of these

Solution:

332.ย  In a series RL circuit,

A.ย  VT lags VR by 90ยฐ

B.ย  VT leads VR by 90ยฐ

C.ย  VR and I are in phase

D.ย  both B and C

Solution:

333.ย  In a series RL circuit where XL = R, the phase angle, ฮธZ, is

A.ย  -45ยฐ

B.ย  0ยฐ

C.ย  90ยฐ

D.ย  45ยฐ

Solution:
In a series RL circuit where the inductive reactance (XL) is equal to the resistance (R), it implies that the phase angle between the voltage and the current is 45 degrees, as the impedance (Z) is purely resistive. Therefore, the correct answer is:

D. 45ยฐ

334.ย  In an ac circuit with only series resistances

A.ย  VT and I are in phase

B.ย  RT =R1 + R2 + R3 + โฆ + etc.

C.ย  each voltage drop is in phase with the series current

D.ย  all of these

Solution:

335.ย  The unit of apparent power is the

A.ย  volt-ampere (VA)

B.ย  watt (W)

C.ย  volt-ampere-reactive (VAR)

D.ย  joule (J)

Solution:

336.ย  In an ac circuit with only series capacitors

A.ย  VT leads I by 90ยฐ

B.ย  VT lags I by 90ยฐ

C.ย  each capacitor voltage drop leads I by 90ยฐ

D.ย  both A and C

Solution:

337.ย  The unit of real power is the

A.ย  watt (W)

B.ย  volt-ampere (VA)

C.ย  joule (J)

D.ย  volt-ampere-reactive (VAR)

Solution:

338.ย  In a series RLC circuit

A.ย  XL and XC are 180ยฐ out of phase

B.ย  IL and IC are 180ยฐ out of phase

C.ย  XL and XC are 90ยฐ out of phase

D.ย  XL and XC are in phase

Solution:

339.ย  The power factor of an ordinary electric bulb is

A.ย  zero

B.ย  unity

C.ย  slightly more than unity

D.ย  slightly less than unity

Solution:

340.ย  The power factor of an ac circuit is equal to

A.ย  cosine of the phase angle

B.ย  sine of the phase angle

C.ย  unity for a resistive circuit

D.ย  unity for a reactive circuit

Solution:

341.ย  Ifย f(t)ย = sin tย +ย sin โ2ย tย is passing through R =ย 1ย ohm, whatย is theย power dissipated in 1 ohm resistor?

A.ย  1 W

B.ย  2 W

C.ย  since f(t) in non-periodic, not possible to find power

D.ย  none of these

Solution:

C.ย  PARALLEL CIRCUITS

342.ย  EE Board Exam October 1981

Aย circuitย consistsย ofย XL = j5 ohms,ย XC =ย -j5ย ohmsย and R =ย 5 ohmsย all are connected in parallel. Find the equivalent impedance.

A.ย  5.5 ฮฉ

B.ย  5.0 ฮฉ

C.ย  4.8 ฮฉ

D.ย  5.2 ฮฉ

Solution:

343.ย  EE Board Exam October 1985

Given: Z1ย  =ย  -j2.5 ohms; Z2ย  = j4 ohms; Z3ย  = 5 ohms; Z4ย  = 1 + j5 ohms. If the four impedances are connected in parallel, find the equivalent impedance in ohms.

A.ย  4.1 + j0.72

B.ย  4.3 + j0.45

C.ย  4.2 + j0.35

D.ย  4.0 + j0.97

Solution:

344.ย  EE Board Exam April 1984, April 1987

Three impedances Za = 3 + j4 ohms, Zb = 4 โย  j4 ohmsย  and Zc = j3 ohms are connected in parallel. Solve for the pf of the combination.

B.ย  0.554 lagging

D.ย  0.620 lagging

Solution:

345.ย  EE Board Exam October 1993

A pure capacitance of 530.515 x 10-6 farad and an inductance of 530.515 x 10-4 Henryย  areย  connectedย  in parallelย  acrossย  an acย  powerย  source.ย  Solveย  for the resultant impedance assuming that the frequency is 30 Hz.

A.ย  10 ฮฉ

B.ย  infinite

C.ย  zero

D.ย  undefined

Solution:

346.ย  REE Board Exam March 1998

Aย coilย ofย aย 50-ohmย resistanceย andย of 150 mHย inductanceย is connectedย in parallel with a 50 ฮผF capacitor. What is the power factor of the circuit?

A.ย  80%

B.ย  50%

C.ย  70%

D.ย  60%

Solution:

347.ย  EE Board Exam April 1982

Three impedances Za, Zb and Zc are connected in parallel. If at 60 Hz, Za = j8, Zb = -j2 and Zc = 5 ohms. Solve for the resultant power factor.

A.ย  0.471 lagging

C.ย  0.573 lagging

Solution:

348.ย  REE Board Exam October 1997

A resistor of 50 ohms and an impedance of 100 + j50 ohms are connected in parallel across a 220 volts supply. What is the power factor of the load?

A.ย  96%

B.ย  99%

C.ย  98%

D.ย  95%

Solution:

349.ย  EE Board Exam October 1992

A capacitor of 3.18 microfarads is connected in parallel with a resistance of 2,000ย  ohms.ย  Theย  combinationย  isย  furtherย  connectedย  inย  seriesย  withย  an inductance of 795 mH andย  resistance of 100 ohms across a supply given by e = 400 sin wt + 80 sin (3wt + 60ยฐ). Assume w = 314 radians/sec. Determine the power dissipated.

A.ย  74.66 W

B.ย  78.05 W

C.ย  80.28 W

D.ย  75.66 W

Solution:

350.ย  EE Board Exam October 1992

A capacitor of 3.18 microfarads isย  connected in parallel with a resistance of 2,000ย  ohms.ย  Theย  combinationย  isย  furtherย  connectedย  inย  seriesย  withย  an inductance of 795 mH and resistance of 100 ohms across a supply given by e = 400 sin wt + 80 sin (3wt + 60ยฐ). Assume w = 314 radians/sec. Determine the circuit power factor.

A.ย  0.702

B.ย  0.650

C.ย  0.633

D.ย  0.612

Solution:

#### Questions and Answers in AC Circuits

Following is the list of practice exam test questions in this brand new series:

MCQ in AC Circuits
PART 1: MCQ from Number 1 โ 50                  Answer key: included
PART 2: MCQ from Number 51 โ 100              Answer key: included
PART 3: MCQ from Number 101 โ 150            Answer key: included
PART 4: MCQ from Number 151 โ 200            Answer key: included
PART 5: MCQ from Number 201 โ 250             Answer key: included
PART 6: MCQ from Number 251 โ 300             Answer key: included
PART 7: MCQ from Number 301 โ 350             Answer key: included
PART 8: MCQ from Number 351 โ 400             Answer key: included
PART 9: MCQ from Number 401 โ 450             Answer key: included
PART 10: MCQ from Number 451 โ 500           Answer key: included

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