This is the Multiple Choice Questions Part 3 of the Series in AC Circuits as one of the Electrical Engineering topic. In Preparation for the REE Board Exam make sure to expose yourself and familiarize in each and every questions compiled here taken from various sources including but not limited to past Board Exam Questions in Electrical Engineering field, Electrical Engineering Books, Journals and other Electrical Engineering References.
Continue Practice Exam Test Questions Part 3 of the Series
SINUSOIDAL VOLTAGE AND CURRENT
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⇐ MCQ in AC Circuits Part 2 | REE Board Exam
101. Each of the three coils generates an e.m.f. of 230 V. The e.m.f. of second leads that of the first 120 V and the third lags behind the first by the same angle. The resultant e.m.f. across the series combination of the coils is ______.
A. 0 V
B. 230 V
C. 690 V
D. none of these
Answer: Option A
Solution:
102. In Fig. 1.4, I1 + I2 is equal to ____.
A. 3 A
B. 4.33 A
C. 9 A
D. 3.43 A
Answer: Option B
Solution:
103. In Fig. 1.4, I2 + I3 is equal to _____.
A. 7 A
B. √13 A
C. 5 A
D. none of these
Answer: Option C
Solution:
104. In Fig. 1.5, E1 + E2 + E3 + E4 is equal to
A. 7 V
B. 5 V
C. 20 V
D. none of these
Answer: Option B
Solution:
105. In Fig. 1.5, ______ will have the least value.
A. E1 + E2 + E3 + E4
B. E1 + E2 + E3 – E4
C. E1 + E2 – E3 – E4
D. -E1 + E4
Answer: Option A
Solution:
106. In a pure resistive a.c. circuit, the frequency of power curve is ____ that of the circuit frequency.
A. half
B. twice
C. thrice
D. same as
Answer: Option B
Solution:
107. In a pure resistive circuit, the instantaneous voltage and current are given by:
v = 250 sin 314t volts
i = 10 sin 314t amperes
The peak power in the circuit is
A. 1250 W
B. 25 W
C. 2500 W
D. 250 W
Answer: Option C
Solution:
108. In a pure resistive circuit, the instantaneous voltage and current are given by:
v = 250 sin 314t volts
i = 10 sin 314t amperes
The average power in the circuit is
A. 2500 W
B. 250 W
C. 25 W
D. 1250 W
Answer: Option D
Solution:
109. An alternating voltage v = Vm sin θ is applied to a pure inductive circuit. The current equation will be
A. i = Im sin θ
B. i = Im sin (θ – π/2 )
C. i = Im sin (θ + π/2 )
D. i = Im sin (θ + π/4 )
Answer: Option B
Solution:
110. The inductive reactance of a circuit is ____ frequency.
A. directly proportional to
B. inversely proportional
C. independent of
D. none of these
Answer: Option A
Solution:
111. Power absorbed in a pure inductive circuit is zero because
A. reactive component of current is zero
B. active component of current is maximum
C. power factor of the circuit is zero
D. reactive and active component of current cancel out
Answer: Option C
Solution:
112. An alternating voltage v = Vm sin θ is applied to a pure capacitive circuit. The current equation will be
A. i = Im sin θ
B. i = Im sin (θ – π/2 )
C. i = Im sin (θ + π/4 )
D. i = Im sin (θ + π/2 )
Answer: Option D
Solution:
113. The capacitive reactance of a circuit is ____ frequency.
A. independent of
B. inversely proportional to
C. directly proportional to
D. none of the above
Answer: Option B
Solution:
114. An a.c. current given by i = 14.14 sin (ωt + π/6) has an rms value of ____ amperes and a phase of ____ degrees.
A. 10, 30
B. 14.14, 180
C. 1.96 , –30
D. 7.07, 210
Answer: Option A
Solution:
115. If e1 = A sin ωt and e2 = B sin (ωt – φ), then
A. e1 legs e2, by θ
B. e2 lags e1 by θ
C. e2 leads e1, by θ
D. e1 is in phase with e2
Answer: Option A
Solution:
116. From the two voltage equations eA = Em sin 100πt and eB = Em sin (100πt + π/6), it is obvious that
A. eA leads eB 30°
B. eB achieves its maximum value 1/600 second before eA does
C. eB lags behind eA
D. eA achieves its zero value 1/ 600 before eB
Answer: Option B
Solution:
117. The r.m.s. value a half-wave rectified current is 10 A, its value for full wave rectification would be ____ amperes.
A. 20
B. 14.14
C. 20/π
D. 40/π
Answer: Option B
Solution:
118. A resultant current is made of two components: a 10 A d.c. components and a sinusoidal component of maximum value 14.14 A. The average value of the resultant current is ____ amperes and r.m.s. value is ____ amperes.
A. 0, 10
B. 24, 24.14
C. 10, 14.14
D. 4.14, 100
Answer: Option C
Solution:
119. The r.m.s. value of sinusoidal ac current is equal to its value at an angle of ____ degree.
A. 60
B. 45
C. 30
D. 90
Answer: Option B
Solution:
120. Two sinusoidal currents are given by the equations: i1 = 10 sin (ωt + π/3) and i2 = 15 sin (ωt – π/4). The phase difference between them is ____ degrees.
A. 105
B. 75
C. 15
D. 60
Answer: Option A
Solution:
121. A sine wave has a frequency of 50 Hz. Its angular frequency is ____ radian/second.
A. 50/π
B. 50/2π
C. 50π
D. 100π
Answer: Option D
Solution:
122. An a.c. current is given by i = 100 sin 100. It will achieve a value of 50 A after ____ second.
A. 1/600 C. 1/1800
B. 1/300 D. 1/900
Answer: Option A
Solution:
123. The reactance offered by a capacitor to alternating current of frequency 50 Hz is 10 Ω. If frequency is increased to 100 Hz reactance becomes ____ ohm.
A. 20
B. 5
C. 2.5
D. 40
Answer: Option B
Solution:
124. A complex current wave is given by i = 5 + 5 sin 100πt ampere. Its average value is ____ ampere.
A. 10
B. 0
C. √50
D. 5
Answer: Option D
Solution:
125. The current through a resistor has a wave form as shown in Fig. 1.6. The reading shown by a moving coil ammeter will be ____ ampere.
A. 5√2
B. 2.5√2
C. 5/π
D. 0
Answer: Option C
Solution:
126. A constant current of 2.8 exists in a resistor. The rms value of current is
A. 2.8 A
B. about 2 A
C. 1.4 A
D. undefined
Answer: Option A
Solution:
127. The rms value of a half-wave rectified symmetrical square wave current of 2 A is
A. √2 A
B. 1 A
C. 1/√ 2 A
D. √3 A
Answer: Option A
Solution:
128. The rms value of the voltage v(t) = 3 + 4 cos (3t) is
A. √17 V
B. 5 V
C. 7 V
D. (3 + 2√2 ) V
Answer: Option A
Solution:
129. The rms value of the resultant current in a wire which carries a dc current of 10 A and a sinusoidal alternating current of peak value 20 A is
A. 14.1 A
B. 17.3 A
C. 22.4 A
D. 30.0 A
Answer: Option B
Solution:
130. For the triangular waveform in the figure, the rms value of voltage is equal to
A. √(1/6) V
B. √(1/3) V
C. 1/3 V
D. √(2/3) V
Answer: Option A
Solution:
131. The rms value of the periodic waveform given in the figure is
A. 2√6 A
B. 6√2 A
C. √(4/3) A
D. 1.5 A
Answer: Option A
Solution:
132. If i1 = 120 cos (100πt + 30°) and i2 = -0.1 cos (100πt + 100°) then i2 leads i1 by ____.
A. -110 degrees
B. 60 degrees
C. -60 degrees
D. 110 degrees
Answer: Option A
Solution:
133. If v1 = sin (ωt + 30°) and v2 = -5 sin (ωt – 15°) then v1 leads v2 by ____.
A. 225 degrees
B. 30 degrees
C. 45 degrees
D. none of these
Answer: Option A
Solution:
134. The rms value of a rectangular wave of period T, having a value of +V for a duration, T1 (<T) and –V for the duration T – T1 = T2 equals ____.
A. V
B. (T1 – T2)/T*V
C. V/√2
D. (T1/T2)* V
Answer: Option A
Solution:
135. The rms value of the voltage waveform v(t) = sin 10t + sin 20t is ____.
A. 1
B. 1/2
C. 1/√2
D. √2
Answer: Option A
Solution:
136. For the voltage waveform v(t) = 2 + cos (ωt + 180°) find the ratio of Vrms/Vave.
A. 3/2√2
B. √3/2
C. π/2
D. π
Answer: Option A
Solution:
137. The rms value of the periodic wave form e(t) shown in the figure is _____.
A. A√(3/2) C. A√(1/3)
B. A√(2/3) D. A√2
Answer: Option B
Solution:
138. Which of the waveforms are having unity peak factor?
A. figure a and b
B. figure b and c
C. figure a and c
D. none of these
Answer: Option B
Solution:
139. The length of time between a point in one cycle to the same point of the next cycle of an AC wave is the ______.
A. frequency
B. period
C. magnitude
D. polarity
Answer: Option B
Solution:
140. In an experiment, a sinusoidal wave form is observed to complete 8 cycles in 25 msec. Determine the frequency of the wave form.
A. 320 Hz
B. 40 Hz
C. 200 Hz
D. 64 Hz
Answer: Option A
Solution:
141. If emf in a circuit is given by e = 100 sin 628t, the maximum value of voltage and frequency is ______.
A. 100 V, 50 Hz
B. 100 V, 100 Hz
C. 50√2 V, 50 Hz
D. 50√2 V, 100 Hz
Answer: Option B
Solution:
142. A sinusoidal voltage wave has an RMS value of 70.71 V and a frequency of 60 Hz. Determine the value of the voltage 0.0014 second after the wave crosses the ωt axis.
A. 70.71 V
B. 100 V
C. 50 V
D. 141.42 V
Answer: Option C
Solution:
143. An alternating current varying sinusoidally with frequency of 50 Hz has an RMS value of 20 A. At what time measured from the positive maximum value will the instantaneous current be 14.14 A?
A. 1/600 sec
B. 1/200 sec
C. 1/300 sec
D. 1/400 sec
Answer: Option A
Solution:
144. The average value of the function i = 50 sin ωt + 30 sin 3ωt is equal to ______.
A. 31.8 A
B. 25 A
C. 38.2 A
D. 51.43 A
Answer: Option C
Solution:
145. For 200 Vrms value triangular wave, the peak value is equal to ______.
A. 200 V
B. 222 V
C. 282 V
D. 346 V
Answer: Option D
Solution:
146. Determine the rms value of a semi-circular current wave which has a maximum value of A.
A. 0.816 A
B. 0.23 A
C. 0.866 A
D. 0.707 A
Answer: Option A
Solution:
147. The rms value of a half-wave rectified current is 100 A. Its value for full-wave rectification would be ______ amperes.
A. 141.4 A
B. 200 A
C. 200/π A
D. 400/π A
Answer: Option A
Solution:
148. A half-wave rectified sine wave has an average value of 100 amp. What is the effective value?
A. 157 A
B. 444 A
C. 70.71 A
D. 100
Answer: Option A
Solution:
149. The form factor of a half-wave rectified alternating current is ______.
A. 1.11
B. 1.57
C. 1.73
D. 1.0
Answer: Option B
Solution:
150. Three alternating currents are given by i1 = 141 sin (ωt + 45°) A; i2 = 30 sin (ωt + 90°) A; i3 = 20 cos (ωt – 120°) A. Find the equation of the resultant current.
A. 167.4 sin (ωt + 45.66°)
B. 74.6 sin ωt
C. 143.8 sin (ωt + 51.4°)
D. 64.7 sin (ωt – 30°)
Answer: Option A
Solution:
⇒ MCQ in AC Circuits Part 4 | REE Board Exam
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