
This is the Multiple Choice Questions Part 11 of the Series in Digital and Data Communication Networks as one of the Communications Engineering topic. In Preparation for the ECE Board Exam make sure to expose yourself and familiarize in each and every questions compiled here taken from various sources including but not limited to past Board Examination Questions in Electronic System and Technologies, Communications Books, Journals and other Communications References.
MCQ Topic Outline included in ECE Board Exam Syllabi
- MCQ in Bit and and Binary Transmission
- MCQ in Signaling Rate
- MCQ in Error Probability, Digital Filtering, Switching, Packet Circuit, Vertical Circuit
- MCQ in Open systems Interconnection
- MCQ in Multiplying, Modulation and Synchronization
- MCQ in Pulse Code Modulation, Companding, Encoding, Bandwidth and Signal to Noise Ratio
- MCQ in Delta Modulation, Slope Overload, Adaptive Delta Modulation, Codes and Protocol
- MCQ in Error Detection and Correction, Digital Carrier systems
- MCQ in Frequency Shift Keying, Phase Shift Keying, Differential Phase Shift keying
- MCQ in DC nature of data transmission, loops, Neutral and Polar
- MCQ in Binary transmission and the concept of time
- MCQ in Asynchronous and Synchronous, timing, Distortion, Bits, band, WPM
- MCQ in Data Interface standards, Data input/output devices
- MCQ in Digital Transmission on analog channel, Modulation-demodulation schemes parameters
- MCQ in Circuit conditioning, Modem Applications
- MCQ in Serial and Parallel Transmission
Continue Practice Exam Test Questions Part 11 of the Series
⇐ MCQ in Digital and Data Communication Networks Part 10 | ECE Board
Choose the letter of the best answer in each questions.
501. The non-coherent FSK needs Eb/N0 than coherent FSK.
A. 1 dB more
B. 1 dB less
C. 3 dB more
D. 3 dB less
Answer: Option A
Solution:
502. The DPSK needs Eb/N0 than BPSK.
A. 1 dB more
B. 1 dB less
C. 3 dB more
D. 3 dB less
Answer: Option A
Solution:
503. Which is easier to implement and is preferred?
A. coherent system
B. non coherent system
C. coherent & non coherent system
D. none of the mentioned
Answer: Option B
Solution:
504. Which is the main system consideration?
A. probability of error
B. system complexity
C. random fading channel
D. all of the mentioned
Answer: Option D
Solution:
505. In the frequency of the carrier signal is varied based on the information in a digital signal
A. ask
B. psk
C. fsk
D. qam
Answer: Option C
Solution:
506. In the amplitude of the carrier signal is varied based on the information in a digital signal
A. ask
B. psk
C. fsk
D. qam
Answer: Option A
Solution:
507. In modulation, the bit rate is 8 times the baud rate
A. 8-qam
B. 64-qam
C. 256-qam
D. none of above
Answer: Option C
Solution:
508. In modulation, the baud rate is 1/4 times the bit rate
A. 4-qam
B. 2-psk
C. 4-psk
D. none of above
Answer: Option D
Solution:
509. Which of the following is not a characteristic of PN sequence?
A. balance property
B. autocorrelation property
C. run property
D. non deterministic
Answer: Option D
Solution:
510. _____ symbols.
A. 2m
B. m
C. 2m
D. 2m-1
Answer: Option D
Solution:
511. PN sequence can be generated using.
A. sequential logic circuits
B. op-amp
C. timer ic
D. mosfet
Answer: Option A
Solution:
512. DSSS system spreads the baseband signal by the baseband pulses with a pseudo noise sequence.
A. adding
B. subtracting
C. multiplying
D. dividing
Answer: Option C
Solution:
513. Frequency hopping involves a periodic change of transmission
A. signal
B. frequency
C. phase
D. amplitude
Answer: Option B
Solution:
514. What is the set of possible carrier frequencies in FH-SS?
A. hopset
B. hop
C. chips
D. symbols
Answer: Option A
Solution:
515. The bandwidth of the channel used in the hopset is called
A. hopping bandwidth
B. total hopping bandwidth
C. instantaneous bandwidth
D. 3 dB bandwidth
Answer: Option C
Solution:
516. The processing gain of FH systems is given by ratio of
A. hopping bandwidth and hopping period
B. instantaneous bandwidth and hopping duration
C. 3 dB bandwidth and bit rate
D. total hopping bandwidth and instantaneous bandwidth
Answer: Option D
Solution:
517. Pseudorandom signal predicted.
A. can be
B. cannot be
C. maybe
D. none of the mentioned
Answer: Option A
Solution:
518. In FH-SS which of the following Modulation Demodulation Technique has been used
A. bpsk
B. fsk
C. ask
D. qam
Answer: Option B
Solution:
519. In DS-SS which of the following Modulation Demodulation Technique has been used
A. bpsk
B. fsk
C. ask
D. qam
Answer: Option A
Solution:
520. Frequency division multiple access (FDMA) assigns channels to users.
A. individual, individual
B. many, individual
C. individual, many
D. many, many
Answer: Option A
Solution:
521. The FDMA channel carries phone circuit at a time.
A. ten
B. two
C. one
D. several
Answer: Option C
Solution:
522. The bandwidth of FDMA channel is
A. wide
B. narrow
C. large
D. zero
Answer: Option B
Solution:
523. The symbol time in FDMA systems is thus intersymbol interference is
A. large, high
B. small, low
C. small, high
D. large, low
Answer: Option D
Solution:
524. Due to transmission scheme bits are needed for overhead in FDMA systems.
A. continuous, few
B. discontinuous, few
C. continuous, many
D. discontinuous, many
Answer: Option A
Solution:
525. ______ is based on FDMA/FDD.
A. gsm
B. w-cdma
C. cordless telephone
D. amps
Answer: Option D
Solution:
526. Which of the following is not true for TDMA?
A. single carrier frequency for single user
B. discontinuous data transmission
C. no requirement of duplexers
D. high transmission rates
Answer: Option A
Solution:
527. Because of transmissions in TDMA, the handoff process in
A. continuous, complex
B. continuous, simple
C. discontinuous, complex
D. discontinuous, simple
Answer: Option D
Solution:
528. _____ synchronization overhead is required in TDMA due to _____ transmission.
A. high, burst
B. high, continuous
C. low, burst
D. no, burst
Answer: Option A
Solution:
529. ______ of TDMA system is a measure of the percentage of transmitted data that contains information as opposed to providing overhead for the access scheme.
A. efficiency
B. figure of merit
C. signal to noise ratio
D. mean
Answer: Option A
Solution:
530. A TDMA system uses 25 MHz for the forward link, which is broken into radio channels of 200 kHz. If 8 speech channels are supported on a single radio channel, how many simultaneous users can be accommodated?
A. 25
B. 200
C. 1600
D. 1000
Answer: Option D
Solution:
531. US digital cellular system based on CDMA was standardized as
A. is-54
B. is-136
C. is-95
D. is-76
Answer: Option C
Solution:
532. Which of the following technique used in CDMA
A. qam
B. gmsk
C. ds-ss bpsk
D. fh-ss fsk
Answer: Option C
Solution:
Questions and Answers in Digital and Data Communication Networks Series
Following is the list of multiple choice questions in this brand new series:
Complete List of MCQ in Communications Engineering per topic
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